2013-01-21 52 views
0

我已經下載從蘋果photopicker這裏的示例代碼蘋果photopicker上傳:http://developer.apple.com/library/ios/#samplecode/PhotoPicker/Introduction/Intro.html#//apple_ref/doc/uid/DTS40010196-Intro-DontLinkElementID_2用PHP拍攝照片到MySQL數據庫

我已經修改了代碼,表示拍攝的照片的結果(節抓拍按鈕)在MyViewController.m:

// as a delegate we are being told a picture was taken 
- (void)didTakePicture:(UIImage *)picture 
{ 
    [self.capturedImages addObject:picture]; 
} 

然後用這一個類似的一個代碼,將其推出到我的Web服務器:

NSData *imageData = UIImageJPEGRepresentation(**_capturedImages.images**, 90); 
NSString *urlString = @"http://localhost/upload.php"; 

NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; 
[request setURL:[NSURL URLWithString:urlString]]; 
[request setHTTPMethod:@"POST"]; 

NSString *boundary = @"---------------------------14737809831466499882746641449"; 
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary]; 
[request addValue:contentType forHTTPHeaderField:@"Content-Type"]; 

NSMutableData *body = [NSMutableData data]; 
[body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[@"Content-Disposition: form-data; name=\"userfile\"; filename=\".jpg\"\r\n" dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[NSData dataWithData:imageData]]; 
[body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; 
[request setHTTPBody:body]; 

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; 

NSLog(returnString); 

我的問題是我不斷收到消息,指出文件無法上傳或代碼剛剛崩潰。

我認爲只是正確訪問得到的圖像並正確推送它的問題。

因爲我不知道如何從這個來自MyViewController.m提取圖像:

@property (nonatomic, retain) **NSMutableArray** *capturedImages; 

PHP代碼的upload.php的是:

<?php 

    $file = basename($_FILES['userfile']['name']); 
    $uploadFile = $file; 
    $randomNumber = rand(0, 99999); 
    $newName = $randomNumber . $uploadFile; 

    echo $file; 

    echo $uploadFile; 

    echo $randomNumber; 

    echo $newName; 

    if (is_uploaded_file($_FILES['userfile']['tmp_name'])) 
    { 
     echo "Temp file uploaded. \r\n"; 
    } 
    else 
    { 
     echo "Temp file not uploaded. \r\n"; 
    } 

    if ($_FILES['userfile']['size']> 300000) { 
     exit("Your file is too large."); 
    } 

    if (move_uploaded_file($_FILES['userfile']['tmp_name'], $newName)) 
    { 
      $postsize = ini_get('post_max_size'); //Not necessary, I was using these 
      $canupload = ini_get('file_uploads'); //server variables to see what was 
      $tempdir = ini_get('upload_tmp_dir'); //going wrong. 
      $maxsize = ini_get('upload_max_filesize'); 

      echo "http://localhost/{$file}" . "\r\n" . $_FILES['userfile']['size'] . "\r\n" . $_FILES['userfile']['type'] ; 
    } 

?> 

感謝

雷吉斯

回答