在for循環中加上隨機生成的數字的總和

Question

class Class1 
{ 

[STAThread] 
    static void Main(string[] args) 
    { 

    int lap, avg = 0; 
    double time = 0; 
    Random generator = new Random(); 
    time = generator.Next(5, 10); 


    for (lap = 1; lap <= 10; lap++) 

    { 

    time = (generator.NextDouble())* 10 + 1; 
    Console.WriteLine("Lap {0} with a lap time of {1} seconds!!!!"lap,time.ToString("##.00")); 

    }// end for 

    Console.WriteLine("The total time it took is {0}",time); 
        Console.WriteLine(); 
    Console.WriteLine(); 
    Console.WriteLine(); 
    Console.WriteLine("Slap the enter key to continue"); 
    Console.ReadLine(); 
    } 
} 
} 

我想教自己的c＃，但是這個問題真的讓我感到莫名其妙。我如何每次通過循環添加時間變量以獲得所有十圈的總和？任何幫助，將不勝感激謝謝:)

Answer 1

如果我沒有得到你，你就需要引入新的變量，以保持總時間：

class Program 
{ 
    [STAThread] 
    static void Main(string[] args) 
    { 
     int lap, avg = 0; 

     Random generator = new Random(); 

     double time = generator.Next(5, 10); 
     double totalTime = 0.0; 

     for (lap = 1; lap <= 10; lap++) 
     { 
      time = (generator.NextDouble())* 10 + 1; 
      Console.WriteLine("Lap {0} with a lap time of {1:##.00} seconds!!!!", 
       lap, time); 

      totalTime += time; 
     } 

     Console.WriteLine("The total time it took is {0}", totalTime); 
     Console.WriteLine(); 
     Console.WriteLine(); 
     Console.WriteLine(); 
     Console.WriteLine("Slap the enter key to continue"); 
     Console.ReadLine(); 
    } 
} 

Answer 2

您需要包括time在以前的價值你加成。

time = time + (generator.NextDouble())* 10 + 1;

或

time += (generator.NextDouble())* 10 + 1;

當然，這將導致你失去當前計算的隨機數。因此，您應該創建另一個變量sumTime，它將存儲所有time值的總和。