蟒蛇分段錯誤

Question

我想顯示在蟒蛇彈出窗口中的消息...所以我寫了這個代碼...請

import sys 
from PyQt4.Qt import * 

class MyPopup(QWidget): 
    def __init__(self): 
     print "6" 
     QWidget.__init__(self) 


class MainWindow(QMainWindow): 
    def __init__(self, *args): 
     print "4" 
     QMainWindow.__init__(self, *args) 
     self.cw = QWidget(self) 
     self.setCentralWidget(self.cw) 
     self.btn1 = QPushButton("Start Chat", self.cw) 
     self.btn1.setGeometry(QRect(50, 30, 100, 30)) 
     self.connect(self.btn1, SIGNAL("clicked()"), self.doit) 
     self.w = None 

    def doit(self): 
     print "5" 
     print "Opening a new popup window..." 
     self.w = MyPopup() 
     self.w.setGeometry(QRect(0, 0, 400, 200)) 
     self.w.show() 

class App(QApplication): 
    def __init__(self, *args): 
     print "3" 
     QApplication.__init__(self, *args) 
     self.main = MainWindow() 
     #self.connect(self, SIGNAL("lastWindowClosed()"), self.byebye) 
     self.main.show() 

    #def byebye(self): 
     #self.exit(0) 

for i in range(1, 5): 
    if __name__ == "__main__": 
     print "1" 
     global app 
     app = App(sys.argv) 
     app.exec_() 
    #main(sys.argv) 
else: 
    print "over" 

這裏第一循環的工作，但是從第二回路即時得到細分故障...傢伙請幫幫我..

Answer 1

在應用程序中應該只有一個QApplication對象。我想你的問題是你試圖在循環中創建幾個。

如果你希望你的用戶關閉主窗口四次實際關閉前，你可以添加事件處理程序：

class MainWindow(QMainWindow): 
    def __init__(self, *args): 
     ... 
     self.counter = 1 

    def closeEvent(self, event): 
     print "closeEvent", self.counter 
     self.counter += 1 
     if self.counter < 5: 
      event.ignore() 
     else: 
      event.accept()