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我發現很難在django模型中規範化字段。我有:django中的非規範化字段
class AnswerSet(models.Model):
title = models.CharField(max_length=255)
num_answers = models.PositiveIntegerField(editable=False, default=0)
answers = models.ManyToManyField(Answer, through='AnswerSetAnswer')
...
class AnswerSetAnswer(models.Model):
answer = models.ForeignKey(Answer)
answer_set = models.ForeignKey(AnswerSet)
...
我希望num_answers包含集合中答案的數量。
如果5個答案最初與AnswerSet「Food」相關聯,並且我編輯了一個答案以便它與AnswerSet「Colors」相關聯,那麼如何重新計算AnswerSet中含有「Food」的答案數?所有的信號似乎只發送新的數據,所以我不能只是重寫保存方法。
我試過使用m2m_changed信號,但是當我通過管理窗體編輯關係時,它永遠不會被調用。
這裏是我的代碼嗎:
def update_answer_set_num_answers(sender, **kwargs):
"""
Updates the num_answers field to reflect the number of answers
associated with this AnswerSet
"""
instance = kwargs.get('instance', False)
print "no instance" # never gets here
if not instance:
return
action = kwargs.get('action')
print "action: ", action
if (action != 'pre_remove' and action != 'pre_add' and action != 'clear'):
return
reverse = kwargs.get('reverse')
if reverse:
answer_set = instance.answer_set
else:
answer_set = instance.answer_set
num_answers = AnswerSetAnswer.objects.filter(answer_set=answer_set.id).count()
if (action == 'pre_remove'):
num_answers -= int(kwargs.get('pk_set'))
elif (action == 'pre_add'):
num_answers += int(kwargs.get('pk_set'))
elif (action == 'clear'):
num_answers = 0
answer_set.num_answers = num_answers
print 'n a: ', answer_set.num_answers
answer_set.save()
m2m_changed.connect(update_answer_set_num_answers, \
AnswerSet.answers.through, weak=False)
是的,它會很方便。例如,我想要顯示5個隨機答案集,它們都有3個答案。我希望有很多答案集,這將有助於擴大規模 – Roger 2010-09-13 20:47:12