檢查數組中的元素是否已被佔用

我正在製作一個雙人遊戲，玩家在1-9網格中輸入一個數字。玩家X用變量Xp輸入所需的位置。玩家O也一樣。但是我不能做一個if語句來檢查玩家是否輸入了已經採用的網格點。檢查數組中的元素是否已被佔用

#include <iostream> 

using namespace std; 

void showBoard(char board[], int turn, int Xp, int Op); 
void winning(char board[]); 


int main() 
{ 

int Xp=0, Op=0, turn=0; 
char board[9] = {'1','2','3','4','5','6','7','8','9'}; 

showBoard(board, turn, Xp, Op); 

return 0; 
} 

void showBoard(char board[], int turn, int Xp, int Op) 
{ 
cout << "Please enter a number on the board that is the spot you wish to use" << endl; 

cout << "Board:\n"; 

cout << board[0] << " " << board[1] << " " << board[2] << endl; 
cout << board[3] << " " << board[4] << " " << board[5] << endl; 
cout << board[6] << " " << board[7] << " " << board[8] << endl; 

do 
{ 
for (turn=1; turn<10; turn++) 
    if (!(turn % 2) == 0) 
    { 
     cout << "\nPlayer X's turn." << endl; 
     cin >> Xp; 
     if(Xp=Op) //HERE IS THE CHECKER 
     { 
      cout << "Spot is taken! Enter new spot: "; 
      cin >> Xp; 
      board[Xp-1] = 'X'; 
     } 
     else 
     { 
     board[Xp-1] = 'X'; 
     }  //WHERE IT ENDS 
cout << "Current Board:\n"; 

cout << board[0] << " " << board[1] << " " << board[2] << endl; 
cout << board[3] << " " << board[4] << " " << board[5] << endl; 
cout << board[6] << " " << board[7] << " " << board[8] << endl; 

winning(board); 
    } 
    else 
    { 
     cout << "\nPlayer O's turn." << endl; 
     cin >> Op; 
     board[Op-1] = 'O'; 

cout << "Current Board:\n"; 

cout << board[0] << " " << board[1] << " " << board[2] << endl; 
cout << board[3] << " " << board[4] << " " << board[5] << endl; 
cout << board[6] << " " << board[7] << " " << board[8] << endl; 

winning(board); 
    } 

}while(turn<10); 

cout << "No one won.\n"; 

return; 
}

來源

2014-04-03 user1810514

數組'在初始化一切「0''，那麼如果它是一個'」 0''你知道這不是招」沒有被採取。 –

'if（Xp = Op）'我相當肯定不會做你認爲的事。嘗試'==' – WhozCraig

另外，嘗試爲兩個玩家使用相同的代碼。 – Deduplicator

初始化一切虛值

說

#define DUMMY_CHAR '.'

，並選擇一個字符爲XP和運算

#define XP_CHAR 'X' 
#define OP_CHAR 'O'

並在您檢查，請

if (board[Xp] != DUMMY_CHAR) // Your checker

來源

2014-04-03 22:01:43 Mohan

首先，你是分配，而不是檢查平等。其次，Xp == Op仍然沒有任何意義。用o點檢查x點？更好的辦法是檢查方如果不是X也不是O：

if(board[Xp - 1] != 'X' || board[Xp - 1] != 'O')

來源

2014-04-03 22:02:27 yizzlez

檢查數組中的元素是否已被佔用

回答

相關問題