如何讓我的應用程序從一個特定的號碼

Question

我想建立一個應用程序來短信迴應說，針對特定號碼的短信，更多的示範，我想這樣的代碼：

if(number == +232344322) 
{ 
    do something 
    } else 
{ 
    do nothing 
    } 

那麼在android中最簡單的方法是什麼？

Answer 1

你需要創建一個BroadcastReceiver這將當短信received.In的BroadCastReceiver的OnReceive編寫代碼來調用retrive短信發送方號碼和比較的數量並基於該任務。

public class ReceiveSMS extends BroadcastReceiver { 
@Override 
public void onReceive(Context context, Intent intent) { 
    final Bundle bundle = intent.getExtras(); 
     if (bundle != null) { 

      final Object[] pdusObj = (Object[]) bundle.get("pdus"); 

      for (int i = 0; i < pdusObj.length; i++) { 

       SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]); 
       String phoneNumber = currentMessage.getDisplayOriginatingAddress(); 
       String message = currentMessage.getDisplayMessageBody(); 
       Log.v("ranjapp", phoneNumber + " " + message); 
       if (phoneNumber.equals("+91xxxxxx"))) { 
        //do something 
       }else{ 
        //do nothing 
       } 
      } 
     } 
    } 
} 

在AndroidManifest.xml你需要添加：

1. ** <application>標籤內意圖過濾器的接收器

   <receiver 
       android:name=".ReceiveSMS" 
       android:exported="true" 
       android:permission="android.permission.BROADCAST_SMS"> 
       <intent-filter> 
        <action android:name="android.provider.Telephony.SMS_RECEIVED" /> 
        <action android:name="android.provider.Telephony.SMS_DELIVER" /> 
       </intent-filter> 
   </receiver> 
   

2. 權限：

   <uses-permission android:name="android.permission.RECEIVE_SMS"/>

   <uses-permission android:name="android.permission.READ_SMS"/>