我被困在一段代碼中,它調用一個jQuery模塊填充表格行id
。我約90%確定這個錯誤在我的jQuery代碼中。一旦我點擊按鈕(class =「view」),我會得到一個未定義的值,而不是行ID
。Table Row attr()問題
感謝您的幫助! leads_queue_a.php的
相關章節:
<section class="main">
<h1>Lead Queue - Assigned Leads</h1>
<div id="lead_wrapper_a"></div>
</section>
fill_leads_a.php:
$cond = array();
$params = array();
if ($_POST['id'] == '') {
return;
}
if (isset($_POST['id']) && $_POST['id'] != '') {
$userID = $_POST['id'];
}
if (!empty($userID)) {
$cond[] = '`users`.`id` = ?';
$params[] = "$userID";
}
$query = "SELECT `leads`.`id`, `leads`.`fname`, `leads`.`lname`, `leads`.`lead_type`, `leads`.`addr_street`, `leads`.`addr_city`, `leads`.`addr_zip`, `leads`.`phone`, `leads`.`phone_alt`, `leads`.`note`, `leads`.`created_by`, `leads`.`created` FROM `leads`,`users`,`leads_assignment`";
if (count($cond)) {
$query .= ' WHERE ' . implode(' AND ', $cond);
}
$query .= ' AND `leads`.`id` = `leads_assignment`.`id_lead`'
. ' AND `users`.`id` = `leads_assignment`.`id_user`';
$stmt = $db->prepare($query);
$stmt->execute($params);
//TABLE BUILDER
$lead = '';
$lead .= '<div class="leads">';
$lead .= '<table class="lead_table">';
$lead .= '<tr>';
$lead .= '<td>Customer</td>';
$lead .= '<td>Phone</td>';
$lead .= '<td>Lead Type</td>';
$lead .= '<td>Status</td>';
$lead .= '<td>Operations</td>';
$lead .= '</tr>';
foreach ($stmt->fetchAll(PDO::FETCH_OBJ) as $row) {
$id = $row->id;
$status = get_statusLast($id);
$fname = $row->fname;
$lname = $row->lname;
$lead_type = $row->lead_type;
$addr_street = $row->addr_street;
$addr_city = $row->addr_city;
$addr_zip = $row->addr_zip;
$phone = $row->phone;
$phone_alt = $row->phone_alt;
$note = $row->note;
$created_by = $row->created_by;
$created = $row->created;
$lead .= "<tr id='$id'>";
$lead .= '<td>' . $fname . ' ' . $lname . '<br />' . $addr_street . '<br />' . $addr_city . ' ' . $addr_zip . '</td>';
$lead .= '<td>' . $phone . '<br />' . $phone_alt . '</td>';
$lead .= '<td>' . $lead_type . '</td>';
$lead .= '<td>' . $status . '</td>';
$lead .= '<td><button type="button" class="view" name="view">View Notes</button><br />'
. '<button type="button" class="update" name="update">Update Status</button></td>';
}
$lead .= '</table>';
$lead .= '</div>';
$db = null;
print $lead;
modul.js培訓相關部分:
$("#lead_wrapper_a").on('click', '.view', function() {
alert($('tr', this).attr('id'));
});
就是這樣!似乎每次我在StackOverflow上問一個問題時,最終都必須等待10分鐘才能接受答案;)你們真棒! –
@WillDavis歡迎您... – PSL