Spring MVC的請求的資源不可用

我想Spring MVC的例子，我不能夠控制從JSP傳送到控制器class.My控制器類是如下Spring MVC的請求的資源不可用

CController.java

package project4; 

import project4.UserDAO1; 
import project4.User1; 
import java.util.Map; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 
import org.springframework.stereotype.Controller; 
import org.springframework.transaction.annotation.Transactional; 
import org.springframework.ui.ModelMap; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.servlet.ModelAndView; 
import org.springframework.web.servlet.mvc.multiaction.MultiActionController; 
import org.springframework.web.bind.annotation.ModelAttribute; 
import org.springframework.validation.BindingResult; 
import org.springframework.beans.factory.annotation.Autowired; 
import org.springframework.beans.factory.annotation.Qualifier; 


@Controller 
@RequestMapping("/frm4") 


public class CController{ 

    private UserDAO1 userDAO; 
    @Autowired 
    @Qualifier("myUserDAO") 
    private UserDAOImpl1 myUserDAO; 

    public void setUserDAO(UserDAO1 userDAO) { 
     this.userDAO = userDAO; 
    } 

    @RequestMapping(params = "add", method = RequestMethod.POST) 
    public ModelAndView add(@ModelAttribute("add") User1 user,HttpServletRequest 
      request,HttpServletResponse response) throws Exception { 
     userDAO.saveUser(user); 
     System.out.println("hai"); 
     return new ModelAndView("redirect:list.htm"); 
    } 

    @RequestMapping(params = "delete", method = RequestMethod.POST) 
    @Transactional 
    public ModelAndView delete(@ModelAttribute("delete") User1 user,HttpServletRequest 
      request,HttpServletResponse response) throws Exception { 
      userDAO.deleteUser(user); 
      return new ModelAndView("redirect:list.htm"); 
    } 


    @RequestMapping(params = "find", method = RequestMethod.POST) 
    @Transactional 
    public ModelAndView find(@ModelAttribute("find") User1 user,HttpServletRequest 
      request,HttpServletResponse response) throws Exception { 
        userDAO.findUser(user); 
         return new ModelAndView("redirect:list.htm"); 
    } 


    @RequestMapping(params = "update", method = RequestMethod.POST) 
    @Transactional 
    public ModelAndView update(@ModelAttribute("update") User1 user,HttpServletRequest 
      request,HttpServletResponse response) throws Exception { 
        userDAO.updateUser(user); 
         return new ModelAndView("redirect:list.htm"); 
    } 

    public ModelAndView list(HttpServletRequest request, 
     HttpServletResponse response) throws Exception { 


     ModelMap modelMap = new ModelMap(); 
     modelMap.addAttribute("userList", userDAO.listUser()); 
     modelMap.addAttribute("user", new User1()); 
     return new ModelAndView("userForm", modelMap); 
    } 
}

和JSP頁面如下

frm4.jsp

<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form method="POST" action="add.do"> 
    <table> 
    <tr> 
     <td><label for="id">Id:</label></td> 
     <td> 
      <input name="id" value="${user.id}" /> 
     </td> 
    </tr> 
    <tr> 
     <td> 
      <label for="name">Name:</label></td> 
     <td> 
      <input name="name" value="${user.name}" /> 
     </td> 
    </tr> 
    <tr> 
     <td> 
      <label for="password">Password:</label></td> 
     <td> 
      <input name="password" value="${user.password}" /> 
     </td> 
     </tr> 

     <tr> 
      <td> 
       <label for="gender">Gender:</label></td> 
      <td> 
       <input name="gender" value="${user.gender}" /> 
      </td> 
     </tr> 
     <tr> 
      <td> 
       <label for="lastName">Country:</label></td> 
      <td> 
      <input name="country" value="${user.country}" /> 
      </td> 
     </tr> 

    </table> 
    <input type="submit" value="Submit"/> 
    </form> 
    </body> 
</html>

我我不使用jsp中春表單標籤（因爲它扔我「既不結合也不是普通的目標對象」錯誤）。所以，當我運行這個程序，我收到以下錯誤作爲

type Status report 

message 

description The requested resource() is not available.

和我得到的網址

http://localhost:8080/Spring/add.do

其中春季是下我已經存儲了program.I都劃歸在src.I「project4」文件夾中的CController.java控制器類我的項目名稱已經把frm4.jsp和的List.jsp在WebContent下。

編輯：

我試圖

<form method="POST" action="CController/add.do">

和

<form method="POST" action="Spring/CController/add.do">

但錯誤是一樣的

來源

2013-04-29 Ezhil

'行動= 「FRM4/add.do」'？ – NINCOMPOOP 2013-04-29 05:33:54

我也試過，但錯誤仍然是一樣的 – Ezhil 2013-04-29 05:36:04

您還沒有定義/add

的任何請求映射

你只需要/frm4你如同附加分離由PARAM名稱的行爲，刪除等

對於這個工作使用action="/frm4"並在表單中添加一個隱藏PARAM名add。

但我會建議將其更改爲獨立網址像FRM4 /添加，FRM4 /刪除等。

@RequestMapping(value = "/add", method = RequestMethod.POST)

來源

2013-04-29 05:52:14

我將它改爲@RequestMapping（value =「frm4/add」，method = RequestMethod.POST）但錯誤保持不變 – Ezhil 2013-04-29 06:30:23

注意值應該是/ add而不是frm4 /添加作爲您的控制器在頂部已經有/ frm4。 – 2013-04-29 06:58:29

在您的spring配置中使用<context:component-scan base-package="<YOUR PACKAGE HERE>"/>爲spring掃描註釋（如果尚未完成）。

類似的問題：Spring MVC Component Scan

來源

2013-04-29 05:59:52 saurabh29july

我已經在配置文件中提供了組件掃描... – Ezhil 2013-04-29 06:21:18

的人，你必須設定行動在形式上與「/ FRM4」

，改變

<input type="submit" value="Submit"/>

到

<input type="submit" name="add" value="Submit"/>

和

@ModelAttribute("add") User1 user

到

@ModelAttribute User1 user

請這些videos

來源

2013-04-29 11:44:27

Spring MVC的請求的資源不可用

回答

相關問題