創建一個MVC ActionResult，它將獲取一個文件列表，將它們壓縮並提供給用戶

Question

我發現了一些使用第三方DLL來完成此操作的代碼，但我希望能夠使用native .net ZipArchive。我到目前爲止的代碼是：

public class ZipResult : ActionResult 
{ 
    private readonly IEnumerable<string> files; 
    private string fileName; 

    public string FileName 
    { 
     get 
     { 
      return fileName ?? "Logfiles.zip"; 
     } 
     set { fileName = value; } 
    } 

    public ZipResult(params string[] files) 
    { 
     this.files = files; 
    } 

    public ZipResult(IEnumerable<string> files) 
    { 
     this.files = files; 
    } 

    public override void ExecuteResult(ControllerContext context) 
    { 
     using (var zipStream = new MemoryStream()) 
     { 
      using (var zip = new ZipArchive(zipStream, ZipArchiveMode.Create, true)) 
      { 
       var entry = zip.CreateEntry("test.txt"); 
       using (var sw = new StreamWriter(entry.Open())) 
       { 
        sw.WriteLine(
         "Etiam eros nunc, hendrerit nec malesuada vitae, pretium at ligula."); 
       } 
      } 

      context.HttpContext 
       .Response.ContentType = "application/zip"; 

      context.HttpContext 
       .Response.AppendHeader("content-disposition", "attachment; filename=" + FileName); 

      zipStream.Position = 0; 

      zipStream.CopyTo(context.HttpContext.Response.OutputStream); 
     } 
    } 
} 

這工作得很好，但顯然沒有任何現有的文件實際上是添加到壓縮文件，它只需創建一個新的文本文件，並補充說。我想要的是能夠傳遞文件列表，並在將文件發回給用戶之前將它們全部添加到存檔中。這是我爲嘗試做這項工作所做的。

public class ZipResult : ActionResult 
{ 
    private readonly IEnumerable<string> files; 
    private string fileName; 

    public string FileName 
    { 
     get 
     { 
      return fileName ?? "Logfiles.zip"; 
     } 
     set { fileName = value; } 
    } 

    public ZipResult(params string[] files) 
    { 
     this.files = files; 
    } 

    public ZipResult(IEnumerable<string> files) 
    { 
     this.files = files; 
    } 

    public override void ExecuteResult(ControllerContext context) 
    { 
     using (var zipStream = new MemoryStream()) 
     { 
      using (var zip = new ZipArchive(zipStream, ZipArchiveMode.Create, true)) 
      { 
       foreach (var file in files) 
       { 
        var entry = zip.CreateEntry(file); 

        using (var writer = new StreamWriter(entry.Open())) 
        { 
         using (var fileStream = new FileStream(file, FileMode.Open)) 
         { 
          fileStream.CopyTo(writer.BaseStream); 
          fileStream.Flush(); 
          fileStream.Close(); 
         } 
        } 
       } 
     } 

      context.HttpContext 
       .Response.ContentType = "application/zip"; 

      context.HttpContext 
       .Response.AppendHeader("content-disposition", "attachment; filename=" + FileName); 

      zipStream.Position = 0; 

      zipStream.CopyTo(context.HttpContext.Response.OutputStream); 
     } 
    } 
} 

此代碼不起作用。它甚至不會將一個文件添加到存檔中。我顯然錯過了一些非常明顯的東西，但我患有密碼盲症。

所有的建議和幫助非常感謝。

乾杯邁克

Answer 1

這裏是工作代碼。原始代碼的主要問題是CreateEntry被賦予了整個路徑，而不僅僅是一個文件名，它實際上是在默默無法創建條目!!!

一旦我解決了這個問題，我還發現System.IO.Compression.FileSystem程序集中有一些很好的擴展方法可以完成這些工作。所以這裏是最終的代碼。

public class ZipResult : ActionResult 
{ 
    private readonly IEnumerable<string> files; 
    private string zipFileName; 

    public string ZipFileName 
    { 
     get 
     { 
      return zipFileName ?? "Logfiles.zip"; 
     } 
     set { zipFileName = value; } 
    } 

    public ZipResult(params string[] files) 
    { 
     this.files = files; 
    } 

    public ZipResult(IEnumerable<string> files) 
    { 
     this.files = files; 
    } 

    public override void ExecuteResult(ControllerContext context) 
    { 
     using (var zipStream = new MemoryStream()) 
     { 
      using (var zipArchive = new ZipArchive(zipStream, ZipArchiveMode.Create, true)) 
      { 
       foreach (var file in files) 
       { 
        var fileName = Path.GetFileName(file); 

        zipArchive.CreateEntryFromFile(file, fileName, CompressionLevel.Optimal); 
       } 
      } 

      context.HttpContext 
       .Response.ContentType = "application/zip"; 

      context.HttpContext 
       .Response.AppendHeader("content-disposition", "attachment; filename=" + ZipFileName); 

      zipStream.Position = 0; 

      zipStream.CopyTo(context.HttpContext.Response.OutputStream); 
     } 
    } 
} 

乾杯邁克