發送數據的PHP和AJAX問題

Question

來自初學者的另一個愚蠢的問題。我有這樣的功能：

$(document).ready(function() { 
    $('#submit-form').click(function(e){ 

     e.preventDefault(); 
     var reg = /^([A-Za-z0-9_\-\.])+\@([A-Za-z0-9_\-\.])+\.([A-Za-z]{2,4})$/; 
     var name  = $('#name').val(), 
      email = $('#email').val(), 
      phone = $('#phone').val(), 
      date  = $('#date').val(), 
      message = $('#message').val(), 
      data_html, 
      success = $('#success'); 

     if(name == "") 
      $('#name').val('Please enter your name.'); 

     if(phone == "") 
      $('#phone').val('Please enter your phone number.'); 

     if(date == "") 
      $('#date').val('Please enter a date and time.'); 

     if(email == ""){ 
      $('#email').val('Your email is required.'); 
     }else if(reg.test(email) == false){ 
      $('#email').val('Invalid Email Address.'); 
     } 

     if(message == "") 
      $('#message').val('Message is required.'); 

     if(message != "" && name != "" && reg.test(email) != false) { 
      data_html = "name=" + name + "&email="+ email + "&message=" + message + "&phone="+ phone + "&date="+ date; 

      //alert(data_html); 
      $.ajax({ 
       type: 'POST', 
       url: '../contact_form.php', 
       data: data_html, 
       success: function(msg){ 

        if (msg == 'sent'){ 
         success.html('<div class="alert alert-success">Message <strong>successfully</strong> sent!</div>') ; 
         $('#name').val(''); 
         $('#phone').val(''); 
         $('#email').val(''); 
         $('#date').val(''); 
         $('#message').val(''); 

        }else{ 
         success.html('<div class="alert alert-error">Message <strong>NOT</strong> sent! Please try again later. </div>') ; 

        } 
       } 
      }); 

     } 
     return false; 
    }); 
}); 

我創造了這個PHP這可能是錯誤的，所以請不要評判我......我仍然在學習:)我是一個總初學者到這個所以請不要給我很難:)

<?php 


$to = 'dvvsfb1@gmail.com'; 

$subject = 'Request a Booking'; 


if($to) { 
$name = $_POST['name']; 
$email = $_POST['email']; 

$fields = array(
    0 => array(
     'text' => 'Name', 
     'val' => $_POST['name'] 
    ), 
    1 => array(
     'text' => 'Email address', 
     'val' => $_POST['email'] 
    ), 
    2 => array(
     'text' => 'Phone', 
     'val' => $_POST['phone'] 
    ), 
    3 => array(
     'text' => 'Date & Time', 
     'val' => $_POST['date'] 
    ), 
    4 => array(
     'text' => 'Message', 
     'val' => $_POST['message'] 
    ) 
); 

$message = ""; 

foreach($fields as $field) { 
    $message .= $field['text'].": " . htmlspecialchars($field['val'],  ENT_QUOTES) . "<br>\n"; 
} 
ini_set("SMTP","aspmx.l.google.com"); 
$headers = "MIME-Version: 1.0\r\nContent-type: text/html; charset=utf-8\r\n"; 
$headers .= "From: \"" . $name . "\" \r\n"; 
$headers .= "Reply-To: " . $email . "\r\n"; 
$message = utf8_decode($message); 

mail($to, $subject, $message, $headers); 

？>

我不斷收到錯誤消息不發送該消息。它不與我的PHP連接，我認爲。有什麼建議？

Answer 1

你不是從你的PHP文件「回答」任何東西。嘗試更換您的「郵件（）」這個叫：

if (mail($to, $subject, $message, $headers)) { 
    echo 'sent'; 
} else { 
    echo 'not sent'; 
} 

Answer 2

在阿賈克斯成功回調，你檢查

if (msg == 'sent') 

其中msg是Ajax請求的響應響應。

但在你的php文件中，你沒有發送任何迴應。嘗試，

$status = mail($to, $subject, $message, $headers); 
echo $status ? 'sent' : 'failed'; 

而在阿賈克斯成功回調，

if($.trim(msg) == 'sent') { 
    //some code 
}