獲得通過分組記錄和剔除重複

Question

我有一個「transaction_status」表：

id transaction_id status 
1   12   0 
2   13   0 
3   12   -1 
4   14   0 
5   13   -1 
6   15   0 
[END OF TABLE] 

我需要得到事務ID只與狀態= 0的記錄。

例如，這就是我要尋找從上表中：

id transaction_id status 
4   14   0 
6   15   0 

到目前爲止，我想：

SELECT id, transaction_id, status 
FROM transaction_status 
WHERE status = 0 OR status = -1 
ORDER BY status ASC 
GROUP BY txn_id 
HAVING status = 0 

，但沒有運氣。我正在用盡想法。請任何想法？謝謝！

Answer 1

在having子句中做了一個小改動。

SELECT id, transaction_id, status 
FROM transaction_status 
WHERE status = 0 OR status = -1 
GROUP BY transaction_id 
HAVING min(status) = 0 

編輯：另外通過，因爲它沒有任何意義

Answer 2

我認爲處理這個最簡單的方法是通過transaction_id使用條件聚集和計數哪個ID只的0狀態相關刪除訂單跟他們。在子查詢中執行此操作，然後返回到主表以檢索所需的完整匹配記錄。

SELECT t1.* 
FROM transaction_status t1 
INNER JOIN 
(
    SELECT transaction_id 
    FROM transaction_status 
    GROUP BY transaction_id 
    HAVING SUM(CASE WHEN status <> 0 THEN 1 ELSE 0 END) = 0 
) t2 
    ON t1.transaction_id = t2.transaction_id 
ORDER BY t1.id DESC 

Answer 3

使用GROUP BY和having條款同時檢查min和max狀態0。

查詢

select `transaction_id` 
from `your_table_name` 
group by`transaction_id` 
having min(`status`) = 0 and max(`status`) = 0;