0
如何使此計數返回爲零?任何時候我想返回的任何字段都等於零,整個查詢返回null?我一直在遇到這個問題,我迫切需要一個解決方案。Cypher計數返回null而不是0
START bp=node({startnodeid})
WITH bp
MATCH (bp)<-[r1?:VIEWED_PROFILE]-()
WHERE r1.timestamp > {weekStart} AND r1.timestamp < {firstDay}
WITH count(r1) AS dayOne, bp
MATCH (bp)<-[r2?:VIEWED_PROFILE]-()
WHERE r2.timestamp > {firstDay} AND r2.timestamp < {secondDay}
WITH count(r2) AS dayTwo, dayOne, bp
MATCH (bp)<-[r3?:VIEWED_PROFILE]-()
WHERE r3.timestamp > {secondDay} AND r3.timestamp < {thirdDay}
WITH count(r3) AS dayThree, dayTwo, dayOne, bp
MATCH (bp)<-[r4?:VIEWED_PROFILE]-()
WHERE r4.timestamp > {thirdDay} AND r4.timestamp < {fourthDay}
WITH count(r4) AS dayFour, dayThree, dayTwo, dayOne, bp
MATCH (bp)<-[r5?:VIEWED_PROFILE]-()
WHERE r5.timestamp > {fourthDay} AND r5.timestamp < {fifthDay}
WITH count(r5) AS dayFive, dayFour, dayThree, dayTwo, dayOne, bp
MATCH (bp)<-[r6?:VIEWED_PROFILE]-()
WHERE r6.timestamp > {fifthDay} AND r6.timestamp < {sixthDay}
WITH count(r6) AS daySix, dayFive, dayFour, dayThree, dayTwo, dayOne, bp
MATCH (bp)<-[r7?:VIEWED_PROFILE]-()
WHERE r7.timestamp > {sixthDay} AND r7.timestamp < {seventhDay}
RETURN count(r7) AS daySeven, daySix, dayFive, dayFour, dayThree, dayTwo, dayOne
由於統計學的原因,我需要前7天的配置文件視圖。
新控制檯:http://console.neo4j.org/?id=cy5v5k
在此控制檯例子中,時間戳是奇數在我的參數如下:
weekStart = 0;
firstDay = 2;
secondDay = 4;
thirdDay = 6;
fourthDay = 8;
fifthDay = 10;
sixthDay = 12;
seventhDay = 14;
和我預期的返回值如下:
dayOne = 1;
dayTwo = 3;
dayThree = 2;
dayFour = 1;
dayFive = 1;
daySix = 4;
daySeven = 0;
我希望我用2.0。我使用1.9。 – user1325194
你能解釋一下在這種情況下計算(1)的數量嗎?我從來沒有見過它像以前那樣使用。 – user1325194
實際上,count(1)仍然沒有返回。 – user1325194