如何統計一個while循環中未選中的複選框

$query = mysql_query("SELECT DISTINCT status, vendor FROM tbl_softwareinstalled WHERE vendor NOT LIKE ''"); 
$nums = mysql_num_rows($query); 
echo "<form name = 'filter' action='softwarefilter.php' method='POST'> 
$nums<br> 

<table border = 1><tr><td>&nbsp;</td> 
<td><strong>Software Vendor</strong></td></tr>"; 

$ctr1 = 1; 
while($fetch = mysql_fetch_array($query)) { 
$vendor = $fetch['vendor']; 
$status = $fetch['status']; 
    if(($ctr1 % 2)==1) 
     { print "<tr bgcolor = 'white'>";} 
     else 
     { print "<tr bgcolor = '#EEEEEE'>"; } 
    print "<td><input name= 'chk[]' type='hidden' value='0'> 
    <input type = 'checkbox' name = 'chk[]' value = '$vendor' "; 




    if ($status == 'Enabled') { 
    print "checked = 'checked'></td><td>$vendor</td></tr>"; } 
    else { 
    print "></td><td>$vendor</td></tr>"; } 
    $ctr1++; 
} 
print "</table>"; 
print "<input type = 'submit' name = 'submit' value = 'Update Filter'> 
</form> "; 


$submit = $_POST['submit']; 
if(isset($submit)) 
{ 
    $chk = $_POST['chk']; 
    $count = count($chk); 

    if (empty($chk)) { 

    echo "qweqwe<br>"; 
    } 

     for ($i=0; $i<$count; $i++) { 
     $abc = $chk[$i]; 
     $query = mysql_query("UPDATE tbl_softwareinstalled SET status = 'Enabled' WHERE vendor = '$abc'"); 

     } 

    echo '<meta http-equiv="refresh" content="0.5;url=/assets/softwarefilter.php"> 
      <script language="javascript"> 
      alert("Software filter updated."); 
      </script>'; 
}

嗨，我該如何計算這段代碼的while循環中的未檢查的複選框？比方說，例如我有10個複選框，其中有10個值，用戶在提交之後選中了3個複選框（值爲：'abc'，'def'，'ghi'）。它會統計所有未經檢查的複選框並回應它的價值。 3複選複選框的值不應被回顯。如何統計一個while循環中未選中的複選框

來源

2011-10-24 theglove

瀏覽器只會告訴你哪些已被查過。從您的數據庫中拉出全部可能的框，然後刪除瀏覽器告訴您的那些已被檢查。

來源

2011-10-24 09:08:45

我曾在一個類似的事情計數未經檢查的框。輸入類型複選框，輸入型的地方兩個輸入字段名稱不同

隱藏

<input type="hidden" class="" name="test[]" value="0"> 
<input type="checkbox" class="" name="checkbox[]" value="1">

然後提交

if (isset($_POST['submit'])) { 
    $cnt = array(); 
    $counter =0; 
    $testcnt = 0; 
    $cnt = 0; 
    if (isset($_POST['test'])) { 
     $testcnt = count($_POST['test']); 
    } 
    if (isset($_POST['checkbox'])) { 
     $cnt = count($_POST['checkbox']); 
    } 
    echo 'the count of unchecked boxes is '; 
    print_r($testcnt-$cnt); 
}

對於您的情況下將其更改爲：

<input name= 'unchecked[]' type='hidden' value='0'>

然後提交當您檢查isset（提交）時，您可以相應地添加以下變化

$unchecked_input = count($_POST['unchecked']); 
$chk = $_POST['chk']; 
$count = count($chk); 
echo $unchecked_input-$count; //will output the count of unchecked boxes

來源

2017-04-01 11:35:54 Sylvester

如何統計一個while循環中未選中的複選框

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