爲什麼我的模型顯示在Django管理禁用？

我生成Django模型動態我的應用程序過程中從YAML描述文件中啓動。我在django管理員註冊他們，但他們在管理界面顯示禁用。看起來像this。爲什麼我的模型顯示在Django管理禁用？

我創建manage.py命令以YAML格式動態地創建描述文件的模型。

from django.core.management.base import BaseCommand 
from django.core.management import call_command 

import yaml 

from generation.generate import generate_fields, generate_model 


class Command(BaseCommand): 
    help = 'Generates or updates django models from specified file' 

    def handle(self, *args, **options): 
     try: 
      f = open(args[0], 'r') 
      models = yaml.safe_load(f) 
      f.close() 
      for name, definition in models.items(): 
       fields = generate_fields(definition['fields']) 
       generate_model(name, definition['title'], fields, "generation", "generation.models") 
      call_command('syncdb', interactive=True) 
     except IOError: 
      self.stderr.write('Cannot open file: {0}'.format(args[0])) 
     except yaml.YAMLError as e: 
      self.stderr.write('Cannot parse file {0}: {1}'.format(args[0], e))

我從根urls.py啓動這個命令是這樣的：

from django.conf.urls import patterns, include, url 
from django.contrib import admin 
from generation import views 
from generation.management.commands.updatemodels import Command 

admin.autodiscover() 

urlpatterns = patterns('', 
    url(r'^$', views.main, name='main'), 
    # url(r'^modgen/', include('modgen.foo.urls')), 

    url(r'^admin/', include(admin.site.urls)), 
) 

Command().handle('models.yaml')

我生成模型，並以這種方式在管理註冊：

from sys import stderr 
from django.contrib import admin 
from django.db import models 


class Types(): 
    INT = 'int' 
    CHAR = 'char' 
    DATE = 'date' 


def generate_model(model_name, model_title, fields, app_label, module): 
    class Meta: 
     pass 
    if app_label: 
     setattr(Meta, 'app_label', app_label) 
    if model_title: 
     setattr(Meta, 'verbose_name_plural', model_title) 
    attrs = {'__module__': module, 'Meta': Meta} 
    if fields is not None: 
     attrs = dict(attrs.items() + fields.items()) 
    model = type(model_name, (models.Model,), attrs) 
    admin.site.register(model) 


def generate_fields(definition): 
    fields = {} 
    for field in definition: 
     fields[field['id']] = generate_field(field['title'], field['type']) 
    return fields 


def generate_field(title, field_type): 
    if field_type == Types.CHAR: 
     return models.CharField(title, max_length=255) 
    elif field_type == Types.INT: 
     return models.IntegerField(title) 
    elif field_type == Types.DATE: 
     return models.DateField(title) 
    else: 
     stderr.write('Unknown field type specified: {0}'.format(field_type))

爲什麼模特展示了殘疾人在管理界面？ Django成功註冊它們。

來源

2013-04-07 Yuriy

還有一個類似的問題這裏：[Django管理登記從動作動態模型（http://stackoverflow.com/questions/13184154/django-admin-registering-dynamic-model-from-action）。但它也沒有解決。 – Yuriy 2013-04-08 05:41:56

也許，首先你需要編輯（或創建）文件generation/admin.py，然後添加以下代碼在Django的管理部分登記的應用模式。

from django.contrib import admin 
from myproject.generation.models import Rooms, Users 

class RoomsAdmin(admin.ModelAdmin): 
    pass 


class UsersAdmin(admin.ModelAdmin): 
    pass 


admin.site.register(Rooms, RoomsAdmin) 
admin.site.register(Users, UsersAdmin)

來源

2013-04-08 02:00:43 zen11625

不幸的是，這不會幫助我，因爲我動態創建的模型。我不知道我會創造什麼車型，直到我的Django應用程序的啓動起來。 – Yuriy 2013-04-08 18:01:48

爲什麼我的模型顯示在Django管理禁用？

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