DOM解析Android中

Question

我一直在使用DOM解析器解析XML，但是當XML元素包含沒有價值，它拋出空指針Exception.how檢查呢？... 這裏我的代碼

NodeList TrackName1 = fstElmnt2.getElementsByTagName("Artist_Name");  


        Element TrackElement1 = (Element) TrackName1.item(0); 

        TrackName1 = TrackElement1.getChildNodes(); 
        result=result+((Node) TrackName1.item(0)).getNodeValue() 

        String Artistname=((Node)TrackName1.item(0)).getNodeValue(); 



              } 

Answer 1

只是檢查爲null之前，嘗試使用該值？

Object value = ((Node) TrackName1.item(0)).getNodeValue(); 
if (value != null) { 
    result = result + value; 
} 

Answer 2

NodeList nodeList = doc.getElementsByTagName("item"); 

         description = new TextView[nodeList.getLength()]; 

      for (int i = 0; i < nodeList.getLength(); i++) { 

       Node node = nodeList.item(i); 


       description[i] = new TextView(this); 

       Element fstElmnt = (Element) node; 

       NodeList dataList = fstElmnt.getElementsByTagName("description"); 
       Element dataElement = (Element) dataList.item(0); 
       dataList = dataElement.getChildNodes(); 
       description[i].setText(((Node) dataList.item(0)).getNodeValue());