PHP array_diff：奇怪的行爲

Question

我有2個相同的PHP數組。只有一個值不同。我想找到這個值：

var_dump(array_diff(array(
    "a" => "1", 
    "b" => "SomeString", 
    "c" => 1, // <- different value, same key 
    "d" => "4521", 
    "e" => "7546654241", 
    "f" => "78", 
    "g" => "99.999", 
    "h" => "34", 
    "i" => "http://google.com/" 
), array(
    "a" => "1", 
    "b" => "SomeString", 
    "c" => "0", // <- different value, same key 
    "d" => "4521", 
    "e" => "7546654241", 
    "f" => "78", 
    "g" => "99.999", 
    "h" => "34", 
    "i" => "http://google.com/" 
))); 

結果是array(0) { }但應該有新的"c"價值，但並非如此。當我刪除所有其他值：

var_dump(array_diff(array(
    "c" => 1 
), array(
    "c" => "0" 
))); 

我得到了我想要array(1) { ["c"]=> int(1) }。

我沒有低估它。爲什麼這樣？

Answer 1

和array_diff（）從所述第一陣列值匹配到第二

returns the values in array1 that are not present in any of the other arrays.

第一陣列中的關鍵c價值1不存在第二陣列爲關鍵a的值，所以沒有區別有沒有和array_diff（）將識別

也許使用array_diff_assoc()將GVE你結果你實際上試圖得到...... http://ideone.com/xHCVfF

Answer 2

我試圖與http://php.net/manual/en/function.array-diff-assoc.php和我得到

array (size=1) 
    'c' => int 1 

作爲使用和array_diff它比較值...