嗯,我把我的Gmail地址和我的通行證放在2個EditTexts中,當我點擊確定按鈕時,我嘗試用我的Gmail郵件api發送郵件。但如果我把錯誤的數據,它不認證,因此我不會發送電子郵件。如果我再次啓動應用程序並使用真實數據,則無法再次進行身份驗證。我做錯了什麼或者是用java mail api完成的事情嗎?下面是我用什麼方法發送電子郵件:第二次身份驗證失敗Java郵件API
public GmailSender(String user, String password) {
this.user = user;
this.password = password;
Properties props = new Properties();
props.setProperty("mail.transport.protocol", "smtp");
props.setProperty("mail.host", mailhost);
props.put("mail.smtp.auth", "true");
props.put("mail.smtp.port", "465");
props.put("mail.smtp.port", "587");
props.put("mail.smtp.socketFactory.port", "465");
props.put("mail.smtp.socketFactory.port", "587");
props.put("mail.smtp.socketFactory.class","javax.net.ssl.SSLSocketFactory");
props.put("mail.smtp.socketFactory.fallback", "false");
props.setProperty("mail.smtp.quitwait", "false");
session = Session.getDefaultInstance(props, this);
}
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication(user, password);
}
public synchronized void sendMail(String subject, String body, String sender, String recipients) throws Exception {
MimeMessage message = new MimeMessage(session);
DataHandler handler = new DataHandler(new ByteArrayDataSource(body.getBytes(), "text/plain"));
message.setSender(new InternetAddress(sender));
message.setSubject(subject);
message.setDataHandler(handler);
if (recipients.indexOf(',') > 0)
message.setRecipients(Message.RecipientType.TO, InternetAddress.parse(recipients));
else
message.setRecipient(Message.RecipientType.TO, new InternetAddress(recipients));
Transport.send(message);
}
public class ByteArrayDataSource implements DataSource {
private byte[] data;
private String type;
public ByteArrayDataSource(byte[] data, String type) {
super();
this.data = data;
this.type = type;
}
public ByteArrayDataSource(byte[] data) {
super();
this.data = data;
}
public void setType(String type) {
this.type = type;
}
public String getContentType() {
if (type == null)
return "application/octet-stream";
else
return type;
}
public InputStream getInputStream() throws IOException {
return new ByteArrayInputStream(data);
}
public String getName() {
return "ByteArrayDataSource";
}
public OutputStream getOutputStream() throws IOException {
throw new IOException("Not Supported");
}
}
} 這裏是我從logcat中得到
12-07 09:58:50.781: E/Validate(595): println needs a message
12-07 09:58:50.781: E/Validate(595): java.lang.NullPointerException: println needs a message
12-07 09:58:50.781: E/Validate(595): at android.util.Log.println_native(Native Method)
12-07 09:58:50.781: E/Validate(595): at android.util.Log.i(Log.java:143)
12-07 09:58:50.781: E/Validate(595): at stathis.example.teliko.Data.onClick(Data.java:107)
12-07 09:58:50.781: E/Validate(595): at android.view.View.performClick(View.java:2408)
12-07 09:58:50.781: E/Validate(595): at android.view.View$PerformClick.run(View.java:8816)
12-07 09:58:50.781: E/Validate(595): at android.os.Handler.handleCallback(Handler.java:587)
12-07 09:58:50.781: E/Validate(595): at android.os.Handler.dispatchMessage(Handler.java:92)
12-07 09:58:50.781: E/Validate(595): at android.os.Looper.loop(Looper.java:123)
12-07 09:58:50.781: E/Validate(595): at android.app.ActivityThread.main(ActivityThread.java:4627)
12-07 09:58:50.781: E/Validate(595): at java.lang.reflect.Method.invokeNative(Native Method)
12-07 09:58:50.781: E/Validate(595): at java.lang.reflect.Method.invoke(Method.java:521)
12-07 09:58:50.781: E/Validate(595): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:868)
12-07 09:58:50.781: E/Validate(595): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:626)
12-07 09:58:50.781: E/Validate(595): at dalvik.system.NativeStart.main(Native Method)
來自服務器的迴應。 – hovanessyan
當然,但我該如何做到? – dothedos
你在logcat中有一些輸出嗎? – hovanessyan