如何從另一臺基於第一臺獲得SUM在MySQL

Question

---------------colete-------------------- 
| id | id_comanda | status | id_lista | 
---------------------------------------- 
| | 21775  | 0  | 3820  | 
---------------------------------------- 
| | 21776  | 0  | 3820  | 
---------------------------------------- 
| | 21777  | 0  | 3820  | 
---------------------------------------- 


-----comenzi-------- 
| id | taxComanda | 
-------------------- 
|21775| 16.00  | 
-------------------- 
|21776| 00.00  | 
-------------------- 
|21777| 16.00  | 
-------------------- 

我想從表colete使得從id_lista列的選擇，以獲得從表comenzi從taxaComand列總和，所以在最後的總和是32.00

這是我有，但並不好：

SELECT a.id_comnda AS a_id_comanda, a.id_lista AS a_id_lista, 
b.id AS b_id, b.taxaComanda AS b_taxaComanda 
(SELECT sum(taxaComanda) FROM comenzi WHERE b.id = a.id_comanda AS totalTaxaComanda) 
FROM colete a 
INNER JOIN comenzi b ON b.id = a.id_comanda 
WHERE a.id_lista = 3820 
GROUP BY a.id_comanda 

Answer 1

基於您的評論我看不到對方的回答莫過於：

SELECT SUM(b.taxComanda) 
FROM colete a 
INNER JOIN comenzi b ON b.id = a.id_comanda 
WHERE a.id_lista = 3820 

Answer 2

使用子查詢和分組id_lista：

SELECT id_lista, SUM(taxComanda) as result, 
FROM(
    SELECT id_comanda , status , id_lista, taxComanda 
    from colete 
    left join comenzi on colete.id = comenzi.id_comanda)as sq 
group by sq.id_lista