檢查列表中的某些元素是否相同

Question

所以我一直在這個問題上待了一段時間，並且在搜索多個其他問題之後找不到我需要的答案。

我已經設置了一個任務來創建一個4位數的隨機數發生器，然後用戶必須嘗試猜測數字。每次嘗試他們都會說明他們有多少號碼，他們是在哪個位置。 此外，號碼需要處於正確的位置。

這是我當前的代碼。

import random as r 
def GetNumber(): 
    number = [r.randint(0, 9), r.randint(0, 9), r.randint(0, 9), r.randint(0, 9)] 
    return number 

def Choices(): 
    randomNumber = GetNumber() 
    userChoice = list(input("Enter 4 numbers\n")) #Allows the user to input a number 4 digits long 
    userChoice = [int(i) for i in userChoice] 
    if userChoice == randomNumber: 
     print("Congratulations! You chose the right number") 

感謝提前:)

Answer 1

這是我的承擔。

import random as r 


def GetNumber(): 
    return [r.randint(0, 9) for i in range(4)] 


def Choices(): 
    randomNumber = GetNumber() 
    userChoice = [int(i) for i in list(input("Enter 4 numbers\n"))] 
    n = 0 
    while userChoice != randomNumber: 
     hits = [str(i+1) for i in range(4) if userChoice[i] == randomNumber[i]] 
     if hits: 
      print('You got position(s) {} correct'.format(', '.join(hits))) 
     else: 
      print('You got all of them wrong!') 
     userChoice = [int(i) for i in list(input("Enter 4 numbers\n"))] 
     n += 1 
    print("Congratulations! You found the right number in {} turns!!".format(n)) 

Choices() 

該代碼已重構了一下循環，直到用戶實際找到密碼。這只是一個框架，您可以嘗試一下，並嘗試根據用戶交互或其他方面進一步優化它。

如果有什麼不清楚的地方，請告訴我。乾杯!

Answer 2

可以zip隨機數和用戶的選擇和比較對：無論

>>> number = [4, 3, 9, 1] 
>>> choice = [1, 3, 4, 1] 
>>> [n == c for n, c in zip(number, choice)] 
[False, True, False, True] 
>>> sum(n == c for n, c in zip(number, choice)) 
2 

要獲得匹配的號碼的總數，其位置，您可以通過Counter提供號碼和用戶的選擇，並與&交叉：

>>> from collections import Counter 
>>> Counter(number) & Counter(choice) 
Counter({1: 1, 3: 1, 4: 1}) 
>>> sum((Counter(number) & Counter(choice)).values()) 
3 

Answer 3

import random as r 
def GetNumber(): 
    number = r.randint(0000, 9999) 
    return str(number).zfill(4) 

def Choices(): 
    randomNumber = GetNumber() 
    print type(randomNumber),randomNumber 
    userChoice = str(input("Enter 4 numbers\n")).strip("\n") #Allows the user to input a number 4 digits long 
    for a,b in zip(userChoice,randomNumber): 
     if not a==b: 
     print "{0} not match {1}".format(a,b) 
    if userChoice==randomNumber: 
     print "Congratulations! You chose the right number" 

Choices() 

Answer 4

我認爲這個關鍵是使用一串數字而不是數字數據類型。這是一個工作示例。你可以通過比較數字來做到這一點，但在這種情況下，我們並不在乎數字的價值，就像字符的模式一樣。

from random import choice 
from string import digits 


def is_digits(string): 
    """Return true if all characters are digits, otherwise false""" 

    return all([char.isdigit() for char in string]) 


def get_number(length): 
    """Return a string of digits with the number of characters equal to length""" 

    return ''.join(choice(digits) for i in range(length)) 


def guess(): 
    """Receive and evaluate guesses for match to randomly generated number""" 

    guess = '' 
    miss_char = '-' 
    miss_message = 'Try again.' 
    win_message = 'Congratulations! You chose the right number.' 
    answer_length = 4 
    answer = get_number(answer_length) 
    while guess != answer: 
     guess = raw_input('Enter {0} numbers: '.format(len(answer))) 
     if len(guess) != len(answer) or is_digits(guess) is False: 
      continue 
     matches = [answer[i] 
        if answer[i] == guess[i] 
        else miss_char 
        for i in range(len(answer))] 
     matches_string = ''.join(matches) 
     message_base = 'Matched digits: {0}.'.format(matches_string) 
     if guess != answer: 
      print(' '.join([message_base, miss_message])) 
      guess = '' 
     else: 
      print(' '.join([message_base, win_message])) 

guess()