這只是丹尼爾之後的另一種想法。它看起來像你的Grids
只是Colors
它可能不會爲一個小的「網格」做很多事情,但是爲Color
製作一個Unbox
實例相對比較容易。然後一個網格將包含一個未裝箱的數組。在Grid.hs
中,您將導入Data.Vector.Unboxed
而不是Data.Vector
。這通常是多更好的原因有很多,但會要求你對許多定義加上Unbox a =>
約束。如果您想將網格映射爲除Color
之外的其他類型的網格,則這可能會產生後果,除非它具有Unbox
實例。
下面我剛剛從vector-th-unbox
(我剛剛瞭解到該軟件包,並且正在考慮再次測試它)和兩個必需的定義中添加TH咒語。在Data.Vector.Unboxed.Base
的Bool實例中手動編寫它並不困難。
{-#LANGUAGE TemplateHaskell, TypeFamilies, MultiParamTypeClasses#-}
module Color where
import Display
import Data.Vector.Unboxed.Deriving
import qualified Data.Vector.Unboxed as V
import qualified Data.Vector.Generic as G
import qualified Data.Vector.Generic.Mutable as M
import Data.Word (Word8)
data Color = Yellow | Red | Green | Blue | Empty
deriving (Show, Eq, Ord, Enum, Bounded)
fromColor :: Color -> Word8
{-# INLINE fromColor #-}
fromColor = fromIntegral . fromEnum
toColor :: Word8 -> Color
{-# INLINE toColor #-}
toColor x | x < 5 = toEnum (fromIntegral x)
toColor _ = Empty
derivingUnbox "Color"
[t| Color -> Word8 |]
[| fromColor |]
[| toColor |]
-- test
colorCycle :: Int -> V.Vector Color
colorCycle n = V.unfoldr colorop 0 where
colorop m | m < n = Just (toColor (fromIntegral (m `mod` 5)),m+1)
colorop _ = Nothing
-- *Colour> colorCycle 12
-- fromList [Yellow,Red,Green,Blue,Empty,Yellow,
-- Red,Green,Blue,Empty,Yellow,Red]
colorBlack = "\ESC[0;30m"
colorRed = "\ESC[0;31m"
colorGreen = "\ESC[0;32m"
colorYellow = "\ESC[0;33m"
colorBlue = "\ESC[0;34m"
instance Display Color where
display Red = colorRed ++ "R" ++ colorBlack
display Green = colorGreen ++ "G" ++ colorBlack
display Yellow = colorYellow ++ "Y" ++ colorBlack
display Blue = colorBlue ++ "B" ++ colorBlack
display Empty = "."
編輯:在vector-th-unbox
版本0.1
以下模板前使用:
derivingUnbox "Color"
[d| instance Unbox' (Color) Word8 |]
[| fromColor |]
[| toColor |]
謝謝!這在另一個地方解決了這個問題。 – Drew