笨3 get_where SQL查詢功能

Question

有這個疑問，

$acc = $this->db->get_where('accounts', array('username' => $username), 1); 

我遇到的問題是，每當我嘗試呼應它（通過print_r的），這是結果，爲什麼它返回一個對象？

CI_DB_mysqli_result Object ( 
    [conn_id] => mysqli Object ( 
     [affected_rows] => 1 
     [client_info] => mysqlnd 5.0.11-dev - 20120503 - $Id: 76b08b24596e12d4553bd41fc93cccd5bac2fe7a $ 
     [client_version] => 50011 
     [connect_errno] => 0 
     [connect_error] => 
     [errno] => 0 
     [error] => 
     [error_list] => Array () 
     [field_count] => 5 
     [host_info] => localhost via TCP/IP 
     [info] => 
     [insert_id] => 0 
     [server_info] => 5.7.14 
     [server_version] => 50714 
     [stat] => Uptime: 16045 Threads: 3 Questions: 382 Slow queries: 0 Opens: 121 Flush tables: 1 Open tables: 114 Queries per second avg: 0.023 
     [sqlstate] => 00000 
     [protocol_version] => 10 
     [thread_id] => 3 
     [warning_count] => 0 
    ) 
    [result_id] => mysqli_result Object ( 
     [current_field] => 0 
     [field_count] => 5 
     [lengths] => 
     [num_rows] => 1 
     [type] => 0 
    ) 
    [result_array] => Array () 
    [result_object] => Array () 
    [custom_result_object] => Array () 
    [current_row] => 0 
    [num_rows] => 
    [row_data] => 
) 

是不是應該返回一個數組值？

https://www.codeigniter.com/userguide2/database/active_record.html#select

它並不顯示有所以我只是假設在活動記錄類中的任何查詢將返回值。

Answer 1

$acc = $this->db->get_where('accounts', array('username' => $username), 1)->result(); 

或

$acc = $this->db->get_where('accounts', array('username' => $username), 1)->result_array();