爲循環越過跳過javascript

我想做一個簡單的JavaScript猜謎遊戲，我的for循環不斷跳過！這裏是越來越跳過我的代碼的一部分：爲循環越過跳過javascript

for (i = 0; i === tries; i += 1) { 
    isSkipped = false; 
    var guessedNumber = prompt("Guess your number now."); 

    console.log("User guessed number " + guessedNumber); 

    //check if number is correct 
    if (guessedNumber === numberToGuess) { 
     confirm("Hooray, you have guessed the number!"); 
     break; 
    } else if (guessedNumber > numberToGuess) { 
     confirm("A little too high..."); 
    } else { 
     confirm("A little too low..."); 
    } 
}

，這裏是完整的代碼：

//declaring variables 
var numberToGuess; 
var tries; 
var i; 
var isSkipped = true; 

var confirmPlay = confirm("Are you ready to play lobuo's guessing game? The number for you to guess will be a number ranging from 1 to 25."); //does the user want to play? 

if (confirmPlay === true) { 
    console.log("User wants to play"); 
} else { 
    window.location = "http://lobuo.github.io/pages/experiments.html"; 
} //if user wants to play, let them play, else go to website homepage 

numberToGuess = Math.floor((Math.random() * 25) + 1); //sets computer-generated number 

tries = prompt("How many tries would you like?"); //gets amount of tries 
tries = Math.floor(tries); //converts amount of tries to integer from string 

for (i = 0; i === tries; i += 1) { 
    isSkipped = false; 
    var guessedNumber = prompt("Guess your number now."); 

    console.log("User guessed number " + guessedNumber); 

    //check if number is correct 
    if (guessedNumber === numberToGuess) { 
     confirm("Hooray, you have guessed the number!"); 
     break; 
    } else if (guessedNumber > numberToGuess) { 
     confirm("A little too high..."); 
    } else { 
     confirm("A little too low..."); 
    } 
} 

if (isSkipped === true) { 
    console.log("Oh no! The for loop has been skipped!"); 
}

如果您需要任何進一步的細節，只問。

來源

2014-02-23 lobuo

什麼，這是對'i + = 0' ??? – elclanrs

oops ...我修正了這個問題，但還是一無所獲......它應該是i + = 1 – lobuo

只需使用i ++;除了'我===試''不好迭代！ – goseo

當你寫：

for (i = 0; i === tries; i += 0) {

循環，只要重複條件i === tries爲真。例如，如果tries爲3，則在第一次迭代中該條件不成立，並且循環立即結束。

你應該寫：

for (i = 0; i < tries; i++) {

來源

2014-02-23 06:55:54 Barmar

這有幫助。感謝：D – lobuo

此外，您需要使用parseInt()功能在用戶的輸入。

var guessedNumber = parseInt(prompt("Guess your number now."), 10);

代替

var guessedNumber = prompt("Guess your number now.");

來源

2014-02-23 06:53:42

爲什麼downvote，他檢查類型也'猜測數字=== numberToGuess'？ –

@SumanBogati因爲類型無關緊要，因爲無論'Math.floor'後面的數字如何，它都是數字。 –

@ Qantas94Heavy - ？ –

不應該的是這樣的？：

for (i = 0; i < tries; i += 1) {

來源

2014-02-23 06:55:26 juvian

您可能想解釋兩者之間的區別，並提供編輯的代碼。 –

哎呀...沒有注意到你我做了<嘗試。這解決了它。謝謝：D – lobuo

真的嗎？我進入了3次嘗試，它的工作 – juvian

爲循環越過跳過javascript

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