錯誤dialog.show（）;警報對話框

我有一個AlertDialog它工作正常，但我注意到它標誌着我放在一行中的錯誤dialog.show();我不知道我能如何解決它。錯誤dialog.show（）;警報對話框

IngresarAdmin.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      final AlertDialog.Builder mBuilder=new AlertDialog.Builder(InicioSesion_Principal.this); 
      View Mview= getLayoutInflater().inflate(R.layout.zona_restrigida,null); 
      final EditText claveAdmin=(EditText)Mview.findViewById(R.id.Clave_proveedor); 
      Button EntrarClaveAdmin=(Button)Mview.findViewById(R.id.Ingresar_clave_proovedor); 
      EntrarClaveAdmin.setOnClickListener(new View.OnClickListener() { 
       @Override 
       public void onClick(View v) { 
        if (!claveAdmin.getText().toString().isEmpty()){ 
         Intent intent=new Intent(getApplicationContext(), menu_administrador.class); 
         startActivity(intent); 
         overridePendingTransition(R.anim.fade_in, R.anim.fade_out); 
         finish(); 
        } 
        else { 
         Toast.makeText(InicioSesion_Principal.this,"Clave incorrecta",Toast.LENGTH_SHORT).show(); 
        } 
       } 
      }); 
      mBuilder.setView(Mview); 
      AlertDialog dialog=mBuilder.create(); 
      dialog.show(); 
     } 
    });

這是顯示我在dialog.show(); 它不會隨時關閉應用程序的錯誤，但我該如何解決？

android.view.WindowLeaked: Activity com.tienda.app.aplicaciontienda.Iniciar_Sesion_3.InicioSesion_Principal has leaked window com.android.internal.policy.PhoneWindow$DecorView{245d004 V.E...... R......D 0,0-683,503} that was originally added here 
                       at android.view.ViewRootImpl.<init>(ViewRootImpl.java:375) 
                       at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:299) 
                       at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:85) 
                       at android.app.Dialog.show(Dialog.java:319) 
                       at com.tienda.app.aplicaciontienda.Iniciar_Sesion_3.InicioSesion_Principal$3.onClick(InicioSesion_Principal.java:119) 
                       at android.view.View.performClick(View.java:5201) 
                       at android.view.View$PerformClick.run(View.java:21163) 
                       at android.os.Handler.handleCallback(Handler.java:746) 
                       at android.os.Handler.dispatchMessage(Handler.java:95) 
                       at android.os.Looper.loop(Looper.java:148) 
                       at android.app.ActivityThread.main(ActivityThread.java:5443) 
                       at java.lang.reflect.Method.invoke(Native Method) 
                       at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:728) 
                       at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:618)

來源

2017-08-24 Carlos Mario

的可能的複製[活動已泄漏最初加入窗口（https://stackoverflow.com/questions/2850573/activity-has-leaked-window-that-was-originally-added） –

您需要調用.dismiss（）;

if(dialog != null) 
    dialog.dismiss();

來源

2017-08-24 20:21:17 josedlujan

然後他必須這樣說呢？ if（dialog！= null） dialog.dismiss（）; dialog.show（）; –

錯誤dialog.show（）;警報對話框

回答

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