我想用一個測試文件中讀取幾個對象,但我從第二步空步驟4的Java測試文件返回NULL
對於名字,如果我輸入史蒂芬,我想獲得ste123背部(123應該是一個隨機數)
下面是代碼:
public class Lab14Tester
{
public static void main(String[] args)
{
Introduction step1 = new Introduction();
System.out.println(step1.giveline1());
System.out.println(step1.giveline2());
System.out.println(step1.giveline3());
System.out.println(step1.giveline2());
System.out.println(step1.giveline1());
Scanner in= new Scanner(System.in);
System.out.print("\nName: ");
String inputname = in.nextLine();
Username step2 = new Username();
String givename = step2.givename();
System.out.println("Your username is " + givename);
System.out.print("\nGive me a number: ");
int inputnumber =in.nextInt();
OddEven step3 = new OddEven();
System.out.println(step3.givenumbertype());
System.out.print("\nGive me a number grade: ");
double grade = in.nextDouble();
NumberToLetter step4 = new NumberToLetter();
System.out.printf("\n%.1f", grade);
System.out.print(" is equal to a " + step4.giveletter());
}
}
public class Username
{
private String subname;
private int randomnumber;
private String outputname;
public void getname(String inputname)
{
subname = inputname.substring(0,3);
randomnumber = (int)(Math.random()*1000);
outputname = subname + randomnumber;
}
public String givename()
{
return outputname;
}
}
你'Username'類缺乏一個構造函數來設置它的成員變量的值。 –
請勿在註釋中輸入代碼。您的原始帖子。 –
謝謝,我應該創建什麼樣的構造函數? – maymay