anyType元素的架構驗證

Question

我想在編輯一些XML文件時使用Visual Studio的架構驗證。這些文件包含要讀取的序列化對象DataContractSerializer。

<?xml version="1.0" encoding="utf-8" ?> 
<MyRoot xmlns="http://schemas.datacontract.org/2004/07/MyDomain" 
     xmlns:lib="http://schemas.datacontract.org/2004/07/MyLibrary" 
     xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> 
    <MyList xmlns:a="http://schemas.microsoft.com/2003/10/Serialization/Arrays"> 
     <a:anyType i:type="lib:MyObject"> 
      <lib:Identifier>my-identifier</lib:Identifier> 
      <lib:MyProperty>my-property-value</lib:MyProperty> 
     </a:anyType> 
     <a:anyType i:type="lib:MyOtherObject"> 
      <lib:Identifier>my-identifier</lib:Identifier> 
      <lib:MyOtherProperty>my-other-property-value</lib:MyOtherProperty> 
     </a:anyType> 
    </MyList> 
</MyRoot> 

我以前在Visual Studio中的「創建模式」菜單選項生成XSD文件，但編輯仍然顯示此錯誤的<a:anyType元素：

This is an invalid xsi:type 'http://schemas.datacontract.org/2004/07/MyLibrary:MyObject' 

我試圖編輯XSD文件對於「http://schemas.microsoft.com/2003/10/Serialization/Arrays」命名空間，但到目前爲止我還沒有能夠消除這個錯誤。這是XSD文件作爲Visual Studio生成它。

<?xml version="1.0" encoding="utf-8"?> 
<xs:schema xmlns:tns="http://schemas.microsoft.com/2003/10/Serialization/Arrays" attributeFormDefault="unqualified" elementFormDefault="qualified" targetNamespace="http://schemas.microsoft.com/2003/10/Serialization/Arrays" xmlns:xs="http://www.w3.org/2001/XMLSchema"> 
    <xs:import namespace="http://schemas.datacontract.org/2004/07/MyLibrary" /> 
    <xs:element name="anyType"> 
     <xs:complexType> 
      <xs:sequence> 
       <xs:element xmlns:q1="http://schemas.datacontract.org/2004/07/MyLibrary" ref="q1:MyProperty" /> 
      </xs:sequence> 
     </xs:complexType> 
    </xs:element> 
</xs:schema> 

Answer 1

我在這裏做了幾個假設，因爲你沒有提供所有的診斷問題的文件。我將包括可以使用和測試的完整XSD文件，並嘗試適應您的問題。

我會假設你有一個主要的模式像這樣的，它定義了在您的實例的默認命名空間中的元素（我稱之爲DataContract.xsd）：基於

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" 
    xmlns="http://schemas.datacontract.org/2004/07/MyDomain" 
    targetNamespace="http://schemas.datacontract.org/2004/07/MyDomain"> 

    <xs:element name="MyRoot"> 
     <xs:complexType> 
      <xs:sequence> 
       <xs:element ref="MyList"/> 
      </xs:sequence> 
     </xs:complexType> 
    </xs:element> 

    <xs:element name="MyList"> 
     <xs:complexType> 
      <xs:sequence> 
       <xs:any maxOccurs="unbounded"/> 
      </xs:sequence> 
     </xs:complexType> 
    </xs:element> 
</xs:schema> 

您發佈的數據我也假設您的anyType元素基於一個抽象類型，其中MyObject和MyOtherObject都是從中導出的。我把它叫做AbstractObject在下面的例子中（MyLibrary.xsd）：

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" 
    xmlns="http://schemas.datacontract.org/2004/07/MyLibrary" 
    targetNamespace="http://schemas.datacontract.org/2004/07/MyLibrary"> 

    <xs:complexType name="AbstractObject" abstract="true"> 
     <xs:sequence> 
      <xs:element name="Identifier" type="xs:string"/> 
     </xs:sequence> 
    </xs:complexType> 

    <xs:complexType name="MyObject"> 
     <xs:complexContent> 
      <xs:extension base="AbstractObject"> 
       <xs:sequence> 
        <xs:element name="MyProperty" type="xs:string"/> 
       </xs:sequence> 
      </xs:extension> 
     </xs:complexContent> 
    </xs:complexType> 

    <xs:complexType name="MyOtherObject"> 
     <xs:complexContent> 
      <xs:extension base="AbstractObject"> 
       <xs:sequence> 
        <xs:element name="MyOtherProperty" type="xs:string"/> 
       </xs:sequence> 
      </xs:extension> 
     </xs:complexContent> 
    </xs:complexType> 

</xs:schema> 

要允許通過anyType您的實例中使用這些類型，你可以聲明它作爲具有AbstractObject類型（或任何你父被稱爲在實際MyLibrary模式）：

<xs:schema xmlns:tns="http://schemas.microsoft.com/2003/10/Serialization/Arrays" 
      attributeFormDefault="unqualified" 
      elementFormDefault="qualified" 
      targetNamespace="http://schemas.microsoft.com/2003/10/Serialization/Arrays" 
      xmlns:xs="http://www.w3.org/2001/XMLSchema" 
      xmlns:q1="http://schemas.datacontract.org/2004/07/MyLibrary"> 

    <xs:import namespace="http://schemas.datacontract.org/2004/07/MyLibrary" schemaLocation="MyLibrary.xsd"/> 
    <xs:element name="anyType" type="q1:AbstractObject" /> 

</xs:schema> 

由於兩個MyObject和MyOtherObject從AbstractObject推導，它們可被用作類型<anyType>。下面的實例將在此場景中驗證：

<MyRoot 
    xmlns="http://schemas.datacontract.org/2004/07/MyDomain" 
    xmlns:i="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:lib="http://schemas.datacontract.org/2004/07/MyLibrary" 
    i:schemaLocation="http://schemas.datacontract.org/2004/07/MyDomain DataContract.xsd 
         http://schemas.microsoft.com/2003/10/Serialization/Arrays SerializationArrays.xsd"> 

    <MyList xmlns:a="http://schemas.microsoft.com/2003/10/Serialization/Arrays"> 
     <a:anyType i:type="lib:MyObject"> 
      <lib:Identifier>my-identifier</lib:Identifier> 
      <lib:MyProperty>my-property-value</lib:MyProperty> 
     </a:anyType> 
     <a:anyType i:type="lib:MyOtherObject"> 
      <lib:Identifier>my-identifier</lib:Identifier> 
      <lib:MyOtherProperty>my-other-property-value</lib:MyOtherProperty> 
     </a:anyType> 
    </MyList> 
</MyRoot>