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如何從Hibernate中刪除對象?休眠刪除
Session session = HibernateSession.getSessionFactory().openSession();
org.hibernate.Transaction tx = session.beginTransaction();
int q = session.createQuery("from Modele where (model='"+u.getModel() +"' and markaid='"+u.getMarki().getId()+"'").executeUpdate();
// session.delete(u);
session.getTransaction().commit();
信息:不支持!使用AST翻譯...
當使用session.delete(u)
相反,我得到這個
信息:在刪除處理處理瞬態實體
CREATE TABLE modele
(
id serial NOT NULL,
markaid integer NOT NULL,
cena numeric(100,2),
model character varying(32),
CONSTRAINT k_glwny PRIMARY KEY (id),
CONSTRAINT obcy FOREIGN KEY (markaid)
REFERENCES marki (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE CASCADE
)
<hibernate-mapping>
<class name="bazaMap.Modele" table="modele" schema="public">
<id name="id" type="int">
<column name="id" />
<generator class="identity" />
</id>
<many-to-one name="marki" class="bazaMap.Marki" fetch="select">
<column name="markaid" not-null="true" />
</many-to-one>
<property name="cena" type="java.lang.Double">
<column name="cena" scale="0" />
</property>
<property name="model" type="string">
<column name="model" length="32" />
</property>
<set name="wypozyczenias" inverse="true">
<key>
<column name="modelid" not-null="true" />
</key>
<one-to-many class="bazaMap.Wypozyczenia" />
</set>
</class>
</hibernate-mapping>
這does not工作太
session.createQuery("from Modele where model = :mmodel and markaid = :mmarkaid").setParameter("mmodel", u.getModel()).setParameter("mmarkaid", u.getMarki().getId()).executeUpdate();
不連接查詢。最好使用Query對象模板。 http://stackoverflow.com/questions/14458986/hibernate-having-difficulty-with-character-in-hql/14459137#14459137 – Taky
@Taky:最好使用查詢參數或條件來構建動態查詢。 (查詢對象模式不解決查詢的創建)。 –
@StefanSteinegger:我以爲查詢對象模式(http://martinfowler.com/eaaCatalog/queryObject.html)定義模式包含標準和查詢參數,不是嗎? – Taky