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這是我的難點:我需要使用默認的woodType創建一個Chair對象數組。我能夠聲明數組本身,但顯然所有的值都是null。當我嘗試實例化數組中的每個Chair對象時,我遇到錯誤。我不確定在嘗試實例化時我做錯了什麼,請幫忙。在Java中創建對象數組時遇到問題
public class PAssign3 {
public static void main(String[] args) {
TableSet set1 = new TableSet();
TableSet set2 = new TableSet(5, 7, 4);
// Chair chr1 = new Chair();//this works properly, setting wood as Oak
// Chair chr2 = new Chair("Pine");//works
}
}
class TableSet {
Table table = new Table();
private int numOfChairs = 2;
//creates an array that can hold "numOfChairs" references to same num of
//chair objects; does not instantiate chair objects!!!
Chair[] chairArr = new Chair[numOfChairs];
//instantiate each chair object for length of array
//this loop does not work; Error: illegal start of type
for (int i = 0; i < numOfChairs.length; i++) {
chairArr[i] = new Chair();
}
public TableSet() {
}
public TableSet(double width, double length, int numOfChairs) {
table = new Table(width, length);
this.numOfChairs = numOfChairs;
chairArr = new Chair[numOfChairs];
//this loop also does not work; Error: int cannot be dereferenced
for (int i = 0; i < numOfChairs.length; i++) {
chairArr[i] = new Chair();
}
}
public void setNumOfChairs(int numOfChairs) {
this.numOfChairs = numOfChairs;
}
public int getNumOfChairs() {
return numOfChairs;
}
public String getChairWoodType() {
return chairArr[0].getWoodType();
}
}
class Table {
private double width = 6;
private double length = 4;
public Table() {
}
public Table(double width, double length) {
this.width = width;
this.length = length;
}
public void setWidth(double width) {
this.width = (width < 0) ? 0 : width;
}
public void setLength(double length) {
this.length = (length < 0) ? 0 : width;
}
public double getWidth() {
return width;
}
public double getLength() {
return length;
}
}
class Chair {
private String woodType = "Oak";
public Chair() {
}
public Chair(String woodType) {
this.woodType = woodType;
}
public void setWoodType(String woodType) {
this.woodType = woodType;
}
public String getWoodType() {
return woodType;
}
}
看起來像你的'for'循環只是在課堂上浮動。功能代碼不能去那裏。把它放在'TableSet()'構造函數中。 – Zircon
您無法在方法外運行代碼。你的意思是把它放在構造函數中嗎? – shmosel