1
的所有數據更新數據庫,嘗試更新數據庫。jQuery:使用來自ajax-request
對於亞姆在record.names做這樣
從js代碼
var data = {
"jobid": $('#jobid').val(),
"names": $('#names').val(),
"scripttype": $('#testscripts').val()
};
var msg="";
for(i = 1; i <=4; i++) {
data["Param" + i + "Key"] = $('#key' + i).val();
data["Param" + i + "Value"] = $('#value' + i).val();
}
$.ajax({
type: 'post',
url: "/save",
dataType: "json",
data: data
});
在node.js中端
jobsCollection.update({
_id: id
}, {
$set: {
names: record.names,
script: record.scripttype,
// i dont know what should i place in this part???
// i have to set paramkey and paramValues
}
},
{
upsert: true
},
function (err, result) {
if (!err) return context.sendJson([], 404);
});
和record.scripttype得到正確的價值觀。
I don't know how to set values got from the for loop for updating
request going
Request: /save
{ jobid: '',
names: 'first',
scripttype: 'fow',
Param1Key: '1',
Param1Value: 'oneeeeee',
Param2Key: '2',
Param2Value: 'twoooooooo'
etc........
............
}