MYSQL左加入3表包括NULL集

Question

試圖'反向工程'其他SO用戶問題/我的問題的答案，但不能。連接仍然逃避我。我有三個表格：比賽（所有比賽的列表），結果（每場比賽的結果），車手（車手信息）。並非所有車手都在特定賽道參加所有比賽。

比賽表

| race_id | track_id | year | complete | 
+-----------+------------+--------+----------+ 
| 1   | 1   | 2006 | 1  | 
| ...  | ...  | ... | ...  | 
| 21  | 1   | 2007 | 1  | 
| ...  | ...  | ... | ...  | 
| 135  | 1   | 2008 | 1  | 
| ...  | ...  | ... | ...  | 
| 215  | 1   | 2009 | 1  | 
| ...  | ...  | ... | ...  | 
| 292  | 1   | 2010 | 1  | 
| ...  | ...  | ... |...  | 
| 351  | 1   | 2011 | 0  | 
+-----------+------------+--------+----------+ 

結果表

| race_id | driver_id | finish | 
+---------+-----------+--------+ 
| 135  | 1   | 15  | 
| ...  | ...  | ... | 
| 292  | 1   | 6  | 
+---------+-----------+--------+ 

驅動程序表

| driver_id | name  | 
+-----------+------------+ 
| 1   | Joe Driver | 
+-----------+------------+ 

我想要的結果集顯示：

| name  | race_id | year | finish | 
+------------+---------+--------+--------+ 
| Joe Driver | 21  | 2007 | NULL | 
| Joe Driver | 135  | 2008 | 15  | 
| Joe Driver | 215  | 2009 | NULL | 
| Joe Driver | 292  | 2010 | 6  | 
+------------+---------+--------+--------+ 

喬驅動僅在賽跑了4場比賽即是在track_id = 1，2006年後的2和僅包括完成座圈（1）

這是我的當前查詢：

SELECT driver.driver, race.id, race.year, result.finish 
FROM race 
LEFT JOIN result ON race.id = result.race_id 
LEFT JOIN driver ON result.driver_id = driver.driver_id 
WHERE race.track_id = 1 
AND race.year > 2006 
AND race.complete = 1 
AND driver.driver_id = 1 
ORDER BY race.id ASC 

結果我得到只顯示了司機在的比賽：

| name  | race_id | year | finish | 
+------------+---------+--------+--------+ 
| Joe Driver | 135  | 2008 | 15  | 
| Joe Driver | 292  | 2010 | 6  | 
+------------+---------+--------+--------+ 

我敢肯定，我忽略了一個簡單的規則來加入？

謝謝！

Answer 1

SELECT driver.driver, race.id, race.year, result.finish 
FROM race 
CROSS JOIN 
     driver 
LEFT JOIN 
     result 
ON  result.race_id = race.id 
     AND result.driver_id = driver.driver_id 
WHERE race.track_id = 1 
     AND race.year > 2006 
     AND race.complete = 1 
     AND driver.driver_id = 1 
ORDER BY 
     race.id ASC