2016-07-13 71 views
2

我有這樣那樣的JSON字符串的:如何解析使用GSON將json對象數組解析爲JAVA二維數組?

[{ 
    "id": 3, 
    "city": "Ilmenau", 
    "floor": null, 
    "housenumber": "35", 
    "streetname": "Blumenstraße", 
    "zip": "98693" 
}, { 
    "id": 4, 
    "city": "Berlin", 
    "floor": null, 
    "housenumber": "54", 
    "streetname": "Bogdansplatz", 
    "zip": "194354" 
}] 

,我需要它被解析成二維數組,這將是這樣的: enter image description here 我怎樣才能使它使用GSON Java庫? 現在我只寫了這段代碼,返回一個列表:

String s=getJson("SELECT * FROM address;"); 

     JsonParser jsonParser = new JsonParser(); 
     JsonObject jo = (JsonObject)jsonParser.parse(s); 
     JsonArray jsonArr = jo.getAsJsonArray("array"); 
     //jsonArr. 
     Gson googleJson = new Gson(); 
     ArrayList jsonObjList = googleJson.fromJson(jsonArr, ArrayList.class); 
     System.out.println("List size is : "+jsonObjList.size()); 
     System.out.println("List Elements are : "+jsonObjList.toString()); 

但上面的代碼只能與陣列的JSON對象,不適用於字符串我已經如上圖所示。

回答

0

能否請您嘗試以下,並查看結果:

// String 's' holds the JSON 

JsonParser jsonParser = new JsonParser(); 
JsonArray jsonArray = (JsonArray) jsonParser.parse(s); 

// this object is used to get the keys 
JsonObject firstJsonObject = jsonArray.get(0).getAsJsonObject();   
Set<java.util.Map.Entry<String, JsonElement>> entrySet = firstJsonObject.entrySet(); 

// declare two dimensional array 
Object[][] array = new Object[entrySet.size()][jsonArray.size() + 1]; 

// the first column of the two-dimensional array is populated 
Iterator<java.util.Map.Entry<String, JsonElement>> itr = entrySet.iterator(); 
for (int i = 0; itr.hasNext(); i++) { 
    array[i][0] = itr.next().getKey(); 
} 

// the rest of the columns are populated 
for (int i = 0; i < jsonArray.size(); i++) { 
    JsonObject obj = (JsonObject) jsonArray.get(i); 
    for (int j = 0; j < array.length; j++) { 
     String key = array[j][0].toString(); 
     JsonElement value = obj.get(key); 
     array[j][i + 1] = value instanceof JsonNull ? null : value.getAsString(); 
    } 

} 
// now the two dimensional array is fully populated 
+0

是的,我認爲這是一個好主意,但SQL請求之後,我可以得到各個領域的名字,但在你的代碼,他們已經註定。那麼可能會創建一個沒有預定義字段名稱的數組? –

+0

當然你的代碼工作正常 –

+0

嗨@BogdanLashkov你能看看我編輯的答案嗎? –