多的mysqli選擇

<?php 
include"../database_conn.php"; 
$con=mysqli_connect("localhost","admin","123456","ayurveadic"); 

$query_pag_data = "SELECT id from diseases"; 
$result_pag_data = mysql_query($query_pag_data) or die('MySql Error' . mysql_error()); 

while ($row = mysql_fetch_array($result_pag_data)) { 
    $diseases_id = $row['id']; 

    $result = mysqli_query($con,"SELECT $diseases_id FROM treatment WHERE gender_id = '10' AND diseases_id = '$diseases_id'"); 
    $row_gid = mysqli_fetch_array($result); 
    if ($row_gid == TRUE){ 

     $sl_dise = mysqli_query($con,"SELECT Diseases_type, id FROM diseases WHERE id = '$diseases_id'"); 

     $rowss = array(); 
     while($r = mysqli_fetch_assoc($sl_dise)) { 
      $rowss[] = $r; 
     } 
     print json_encode($rowss); 
    } 
}

輸出是：多的mysqli選擇

[{"Diseases_type":"fever","id":"114"}][{"Diseases_type":"rhrh","id":"123"}]

我怎樣才能得到這樣的輸出：

[{"Diseases_type":"fever","id":"114"},{"Diseases_type":"rhrh","id":"123"}]

來源

2014-06-13 yathavan

爲什麼你要混合** mysql _ **和** mysqli _ **。總是首選** mysqli _ **，因爲** mysql _ **已被棄用。 – Ranjith

[PHP將數組合併成一個大數組]可能重複（http://stackoverflow.com/questions/10034521/php-combine-arrays-into-one-big-array） –

需要初始化外循環前的JSON數組，並打印出來在最後，不是每一次。

<?php 
include"../database_conn.php"; 
$con=mysqli_connect("localhost","admin","123456","ayurveadic"); 

$query_pag_data = "SELECT id from diseases"; 
$result_pag_data = mysql_query($query_pag_data) or die('MySql Error' . mysql_error()); 

$rowss = array(); 
while ($row = mysql_fetch_array($result_pag_data)) { 
    $diseases_id = $row['id']; 

    $result = mysqli_query($con,"SELECT $diseases_id FROM treatment WHERE gender_id = '10' AND diseases_id = '$diseases_id'"); 
    $row_gid = mysqli_fetch_array($result); 
    if ($row_gid == TRUE){ 

     $sl_dise = mysqli_query($con,"SELECT Diseases_type, id FROM diseases WHERE id = '$diseases_id'"); 

     while($r = mysqli_fetch_assoc($sl_dise)) { 
      $rowss[] = $r; 
     } 
    } 
} 
print json_encode($rowss);

來源

2014-06-13 06:23:21 Barmar

非常感謝Barmar。 – yathavan

把你結束的這個while ($row = mysql_fetch_array($result_pag_data)) {

print json_encode($rowss);

後還要去掉這個$rowss = array();數組初始化

來源

2014-06-13 06:25:44 Ranjith

這不是他需要改變的全部，因爲他每次循環都重新初始化'$ rowss'。 – Barmar

感謝指出。 – Ranjith

爲什麼downvoted？你能指出我的錯誤嗎？ – Ranjith

這裏是你優化的代碼

<?php 
include"../database_conn.php"; 
$con=mysqli_connect("localhost","admin","123456","ayurveadic"); 

$query_pag_data = "select diseases.Diseases_type,diseases.id from diseases inner join treatment on treatment.diseases_id = diseases.id where treatment.gender_id = '10' "; 
$result_pag_data = mysql_query($query_pag_data) or die('MySql Error' . mysql_error()); 

$rowss = array(); 
while ($row = mysqli_fetch_assoc($result_pag_data)) { 
    $rowss[] = $row; 
} 
print json_encode($rowss); 
?>

來源

2014-06-13 06:27:49 Anish

你爲什麼用SELECT *替換'SELECT Diseases_type，id'？我們應該鼓勵人們選擇特定的專欄。 – Barmar

@Barmar好的。同意和更新的代碼。但爲什麼要投票？ – Anish

我沒有downvote。我最初選擇了，然後解開它直到你解決這個問題。 – Barmar

多的mysqli選擇

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