與會話登錄表單錯誤

Question

我想知道我錯過了哪些錯誤。

我的形式會是這樣

<form id="myForm" action="loginAction" name="login" method="POST"> 
     <p> <label class="inputField" > Email Address : </label> </p> 
     <p> <input class="registerField" id="emailid" name="email" required="required" type="text" placeholder="eg. john.wick@yahoo.com"/> <span class="warning" id="emailWarning"> </p> 

     <p> <label class="inputField" > Password : </label> </p> 
     <p> <input class="registerField" id="textpwd" name="password" required="required" type="password" placeholder="Your password"/> </p> 

    <p> <input name="submit" class="registerButton" type="submit" value="LOGIN"> </p> 

loginAction.php低於

<?php 
// Report all PHP errors 
error_reporting(-1); 

session_start(); 

include 'dbconnect.php'; 

$username = $_POST['email']; 
$password = $_POST['password']; 

$username = mysqli_real_escape_string(stripslashes($username)); 
$password = mysqli_real_escape_string(stripslashes($password)); 

$loginUser = " SELECT registerPassword, emailAddress FROM register_user 
       WHERE emailAddress = '$username' AND registerPassword = '$password'"; 
$loginSuccess = mysqli_query($mysqli, $loginUser) or die(mysqli_error($mysqli)); 
$loginRow = mysqli_num_rows($loginSuccess); 

if($loginRow == 1) { 
    // $_SESSION['login_user'] = $username; 
    echo "SUCCESSFUL LOGIN"; 
    //header ("Location: index"); 
    } else { 
     echo "YOU WRONG"; 
    } 
mysqli_close($mysqli); 

？>

答案是你錯了即使密碼和下面的代碼電子郵件是一樣的。我知道我還沒有完成會議，但這不能登錄，所以我不能做更多的會話。

Answer 1

你形成字段名電子郵件沒有username變化

$username = $_POST['username']; 

到

$username = $_POST['email']; 

而且錯誤報告和

打開PHP標籤像<?php session_start();

Answer 2

之前刪除空格

您在loginAction.php

因爲在你把表格 $username = $_POST['username'];

改變它$username = $_POST['email'];

你寫：

<input id="emailid" name="email" type="text"/>

和

if($loginRow!=0) { 
    // $_SESSION['login_user'] = $username; 
    echo "SUCCESSFUL LOGIN"; 
    //header ("Location: index"); 
    } else { 
     echo "YOU WRONG"; 
    }