我正在VS2012中使用NSubstitute進行測試,並試圖將模型轉換爲列表,或者我可以計算的東西。下面的代碼:在MVC測試中將模型轉換爲列表
[TestMethod]
public void StartedGame()
{
// arrange
var repo = Substitute.For<IGameRepository>();
IEnumerable<Game> expectedGames = new List<Game>
{
new Game{ gameTypeID = 1, hasStarted = false, ID = 1, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 2, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 3, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 4, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 5, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false}
};
repo.GetGames().Returns(expectedGames);
var sut = new GameController(repo);
// act
var actual = sut.GameMenuStart();
// assert
//Assert.IsInstanceOfType(actual, typeof(ViewResult));
var viewResult = actual as ViewResult;
Assert.IsNotNull(viewResult);
}
當我調試,我可以將鼠標懸停在「的ViewResult」看型號,有我看到的條目與「計數」,但我怎麼能達到呢?我試圖鑄造「遊戲」的對象,像這樣:
Game[] theModel = (Game[])viewResult.Model;
並列出多,但總是失敗。 任何想法?
編輯:的ViewResult的類型爲:System.Web.Mvc.ViewResult
下面是代碼的這個函數內的其餘部分:
var repo = Substitute.For<IGameRepository>();
IEnumerable<Game> expectedGames = new List<Game>
{
new Game{ gameTypeID = 1, hasStarted = false, ID = 1, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 2, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 3, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 4, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 5, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false}
};
repo.GetGames().Returns(expectedGames);
var sut = new GameController(repo);
我已經添加了更多,以及viewResult的類型。它不包含'ToArray()'擴展名。 – Mappan 2013-05-14 17:43:02