正則表達式得到以下模式

Question

您好我有下面的代碼行

{ 
.....(here i can have anything, numbers, string special characters 
...."hello" 
} 

我需要知道哪些發現上面的圖案，我正則表達式模式，其中串從{然後一些文本，然後一個關鍵字開始像「你好」然後}。

請幫

，所以我不得不

function test(a,b,c){ 
} 

function test2(c,a,d){ 
if(a > 0){ 
    alert('test'); 
} 

和我得到這個表達function\s+(\S+)\s*\((.|\n)*?\)\s*{

這給了我function test(a,b,c)和

function test2(c,a,d) 

我希望有一個正則表達式，給了我當它找到一個像'測試「內部的功能。

有意義嗎？

Answer 1

我不知道C＃，但像（與.匹配換行）正則表達式：

.*\bfunction\b.+?\bhello\b.+?\} 

應該做的工作。

說明：

The regular expression: 
(?s-imx:.*\bfunction\b.+?\bhello\b.+?\}) 
matches as follows: 

NODE      EXPLANATION 
---------------------------------------------------------------------- 
(?s-imx:     group, but do not capture (with . matching 
         \n) (case-sensitive) (with^and $ matching 
         normally) (matching whitespace and # 
         normally): 
---------------------------------------------------------------------- 
    .*      any character (0 or more times (matching 
          the most amount possible)) 
---------------------------------------------------------------------- 
    \b      the boundary between a word char (\w) and 
          something that is not a word char 
---------------------------------------------------------------------- 
    function     'function' 
---------------------------------------------------------------------- 
    \b      the boundary between a word char (\w) and 
          something that is not a word char 
---------------------------------------------------------------------- 
    .+?      any character (1 or more times (matching 
          the least amount possible)) 
---------------------------------------------------------------------- 
    \b      the boundary between a word char (\w) and 
          something that is not a word char 
---------------------------------------------------------------------- 
    hello     'hello' 
---------------------------------------------------------------------- 
    \b      the boundary between a word char (\w) and 
          something that is not a word char 
---------------------------------------------------------------------- 
    .+?      any character (1 or more times (matching 
          the least amount possible)) 
---------------------------------------------------------------------- 
    \}      '}' 
---------------------------------------------------------------------- 
)      end of grouping 
---------------------------------------------------------------------- 

Answer 2

如何：

MatchCollection matches = Regex.Matches(YourText, @"\{[^}]*""hello"".\}", RegexOptions.Multiline); 
foreach (Match match in matches) 
{ 
    foreach (Capture capture in match.Captures) 
    { 
    Console.WriteLine(capture.Value); 
}