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我編寫的以下C#算法檢測到O(n)時間內無向圖中存在一個循環。它避免了遞歸,並通過字典和散列集來利用散列。但是,我能做得更好嗎?這是在無向圖中檢測週期的最佳算法嗎?
void Main()
{
var graph = new Dictionary<int, HashSet<int>>
{
{ 0, new HashSet<int> { 4 } },
{ 1, new HashSet<int> { 2, 3, 4 } },
{ 2, new HashSet<int> { 1 } },
{ 3, new HashSet<int> { 1, 4 } },
{ 4, new HashSet<int> { 0, 1, 3 } }
};
Console.WriteLine(HasCycle(graph, 0));
}
bool HasCycle(Dictionary<int, HashSet<int>> graph, int start)
{
var stack = new Stack<int>();
var visited = new HashSet<int>();
stack.Push(start);
var curr = start;
var prev = -1;
while (stack.Count > 0)
{
prev = curr;
curr = stack.Pop();
visited.Add(curr);
HashSet<int> neighbors;
if (graph.TryGetValue(curr, out neighbors) && neighbors != null)
{
foreach (var neighbor in neighbors)
{
if (!visited.Contains(neighbor))
{
stack.Push(neighbor);
}
else if (neighbor != prev && neighbors.Contains(prev))
{
return true;
}
}
}
}
return false;
}
如果在迭代時結束於已訪問的節點中,則有循環。 – arboreal84
但對於*無向圖*,您必須確保已訪問的節點不是您剛剛來自的節點。這是我試圖在我的'else'語句中捕獲的邏輯。 –