通過在android

Question

中給出兩次（開始和結束）來獲取所有時隙（1小時的間隔）我有兩次。開始和結束。現在我想在1小時內顯示它們之間的所有時間。

例如：

我有00：00-23：55。

輸出： -

12:00 AM - 上午01:00
上午01:00 - 02:00 AM與等。

請幫我找到它。

在此先感謝。

Answer 1

String date1 = "26/02/2011"; 
String time1 = "00:00 AM"; 
String date2 = "26/02/2011"; 
String time2 = "12:00 PM"; 

String format = "dd/MM/yyyy hh:mm a"; 

SimpleDateFormat sdf = new SimpleDateFormat(format); 

Date dateObj1 = sdf.parse(date1 + " " + time1); 
Date dateObj2 = sdf.parse(date2 + " " + time2); 
System.out.println("Date Start: "+dateObj1); 
System.out.println("Date End: "+dateObj2); 

//Date d = new Date(dateObj1.getTime() + 3600000); 


long dif = dateObj1.getTime(); 
while (dif < dateObj2.getTime()) { 
    Date slot = new Date(dif); 
    System.out.println("Hour Slot --->" + slot); 
    dif += 3600000; 
} 

OUTPUT：

Date Start: Sat Feb 26 00:00:00 IST 2011 
Date End: Sat Feb 26 12:00:00 IST 2011 
Hour Slot --->Sat Feb 26 00:00:00 IST 2011 
Hour Slot --->Sat Feb 26 01:00:00 IST 2011 
Hour Slot --->Sat Feb 26 02:00:00 IST 2011 
Hour Slot --->Sat Feb 26 03:00:00 IST 2011 
Hour Slot --->Sat Feb 26 04:00:00 IST 2011 
Hour Slot --->Sat Feb 26 05:00:00 IST 2011 
Hour Slot --->Sat Feb 26 06:00:00 IST 2011 
Hour Slot --->Sat Feb 26 07:00:00 IST 2011 
Hour Slot --->Sat Feb 26 08:00:00 IST 2011 
Hour Slot --->Sat Feb 26 09:00:00 IST 2011 
Hour Slot --->Sat Feb 26 10:00:00 IST 2011 
Hour Slot --->Sat Feb 26 11:00:00 IST 2011 

Answer 2

命名可能不正確也可以更好地形成，但現在作爲嘗試和錯誤此代碼的作品。

關於00：00-23：55，使用解析它 ' - '，第一部分可以是 '開始時間' 和第二可以是 '結束時間'

package demo.orientaion.change.run_cmd; 

import java.text.ParseException; 
import java.text.SimpleDateFormat; 
import java.util.Calendar; 
import java.util.Date; 
import java.util.GregorianCalendar; 

public class TimeDiffCalc { 

public TimeDiffCalc() { 

} 

public Calendar addHr(String startTime) { 
    SimpleDateFormat df = new SimpleDateFormat("HH:mm"); 
    Date d; 

    Calendar gc = null ; 
    try { 
     d = df.parse(startTime); 

     gc = new GregorianCalendar(); 
     gc.setTime(d); 
     gc.add(Calendar.HOUR, 1); 
    } catch (ParseException e) { 
     e.printStackTrace(); 
    } 
    return gc; 
} 

public void diffCalc(String time1, String time2) { 

    long diff=0; 
    SimpleDateFormat format = new SimpleDateFormat("HH:mm"); 
    Date date1 = null; 
    try { 
     date1 = format.parse(time1); 
     Date date2 = format.parse(time2); 
     diff = date2.getTime() - date1.getTime(); 
     Date date3 ; 
     String string = time1; 
     while(true) 
     { 
      Calendar gc = addHr(string) ; 
      date3 = gc.getTime(); 
      string = getHrMin(gc.get(Calendar.HOUR_OF_DAY))+":"+getHrMin(gc.get(Calendar.MINUTE)); 
      if(date2.getTime()-date3.getTime()>=0) 
      { 
       System.out.println("diff Hours :: "+string); 
      } 
      else 
      { 

       break; 
      } 

     } 

    } catch (ParseException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } 
    System.out.println("Difference in Houres:"+getDate(diff)); 

} 

private String getDate(long diff) { 
    long hours=diff/(60*60*1000); 
    long minutes=(diff%(60*60*1000))/(60*1000); 

    long sec=((diff%(60*60*1000))%(60*1000))/1000; 
    String formateddate=""; 
    if(hours<10) 
    { 
     formateddate="0"+hours; 
    }else{ 
     formateddate=""+hours; 
    } 
    if(minutes<10) 
    { 
     formateddate=formateddate+":0"+minutes; 
    }else{ 
     formateddate=formateddate+":"+minutes; 
    } 
    if(sec<10) 
    { 
     formateddate=formateddate+":0"+sec; 
    }else{ 
     formateddate=formateddate+":"+sec; 
    } 

    return formateddate; 
} 

private String getHrMin(int time) { 
    String formatedTime; 
    if(time<10) 
    { 
     formatedTime="0"+time; 
    }else{ 
     formatedTime=""+time; 
    } 
    return formatedTime; 
} 

/** 
* @param args 
*/ 
public static void main(String[] args) { 
    TimeDiffCalc calc = new TimeDiffCalc(); 

    String startTime = "00:00:00"; 
    String endTime = "23:53:00"; 
    calc.diffCalc(startTime, endTime); 
} 

}