如何以我輸入的ASCII碼顯示所需的值？

Question

我需要Java代碼。請幫幫我。例如：當我在ASCII輸入號碼

0 the output will be nul 
1 for soh 
2 for stx until it reaches the max number of ASCII. 

考慮以下代碼。它輸出一個ASCII碼。我怎樣才能扭轉它？

String test = "ABCD"; 
for (int i = 0; i < test.length(); ++i) { 
    char c = test.charAt(i); 
    int j = (int) c; 
    System.out.println(j); 
} 

Answer 1

import java.io.*; 
import java.lang.*; 
    public class CharToASCII{ 
     public static void main(String args[]) throws IOException{ 
      BufferedReader buff = new BufferedReader(new InputStreamReader(System.in)); 
      System.out.println("Enter the char:"); 
      String str = buff.readLine(); 
      for (int i = 0; i < str.length(); ++i){ 
      char c = str.charAt(i); 
      int j = (int) c;// your work is done here 
      System.out.println("ASCII OF "+c +" = " + j + "."); 
      } 
     } 
     } 

Answer 2

只投一個整數值，如果您需要低於「0」的ASCII值一些文本輸出到char：

int value = (int) 'a'; 
System.out.println((char) value); // prints a 

---

，你需要從整數值的映射（ASCII碼數）字面，像這樣：

String[] literals0to32 = {"NUL", "SOH", "STX", /* to be continued */ }; 

private static String toLiteral(int value) { 

    if (value < 0 || value > 255) 
     throw new IKnowThatIHaveToValidateParametersException(); 

    if (value < 32) 
    return literals0To32[value]; 
    else 
    return (char) value; 
} 

Answer 3

您可以打印相應的Unicode Control Pictures，例如對於012（nul）爲\u2400。

Answer 4

class prg1{ 
    public static void main(char a){ 
     int b=(int)a; 
     System.out.println("ASCII value ="+b); 
    } 
} 

Answer 5

試試這個：

public static void main(String[] args) { 
    String a = "a"; 
    char b = a.charAt(0); 
    int c = b; 
    System.out.println(c); 
}