交互的shell腳本

Question

如何創建一個簡單的shell腳本，要求對來自用戶的簡單輸入，然後只運行與預定義的選擇相關的命令，例如

IF "ON" 
Backup Server 
ELSEIF "OFF" 
Delete Backups 
ELSEIF "GREY" 
Send Backups 
ENDIF 

Answer 1

可以從接受輸入用戶通過read，你可以使用case ... esac塊做不同的事情。

閱讀作爲其參數，爲它會保存它的變量名的值

read foo 

會參加來自用戶的vaue並將其存儲在$foo。

要提示用戶輸入，您需要使用echo。

echo "What is your favourite color?" 
read color 

最後，大多數shell腳本都支持case操作符。其採取的形式

case "value" in 
    "CHOICE) 
     # Do stuff 
     ;; 
esac 

全部放在一起：

echo "Which choice would you like? \c" 
read choice 

case "$choice" in 

    ON) 
     # Do Stuff 
     ;; 
    OFF) 
     # Do different stuff 
     ;; 
    *) 
     echo "$choice is not a valid choice" 
     ;; 
esac 

Answer 2

#!/bin/bash 

select choice in "ON" "OFF" "*"; do 
case "$choice" in 
    ON) echo "$choice"; # do something; 
    break;; 
    OFF) echo "$choice"; # do something; 
    break;; 
    *) echo "$choice other"; # do something; 
    break;; 
esac 
done 

Answer 3

您好是簡單的例子，如何做到這一點

while true; do 
    read -p 'do you want to continue "y" or "n": ' yn 

    case $yn in 

     [Yy]*) echo 'this program continue '; break;; 

     [Nn]*) exit;; 

     *) echo 'Please answer yes or no: ';; 

    esac 

done 

while true; do 
    read -p 'press "c" to quit this program: ' c 

    case $c in 

     [Cc]*) exit;; 

     *) echo 'for quit this program press "c": ' ;; 

    esac 

done 

源，請點擊這裏source