如何使用AsyncHttpClient進行HTTPS調用？

我使用AsyncHttpClientlink製作HTTP調用，但現在我們的服務器已遷移到HTTPS和我得到異常javax.net.ssl.SSLPeerUnverifiedException: No peer certificate。有沒有人嘗試使用這個庫進行https調用？ AsyncHttpClient的如何使用AsyncHttpClient進行HTTPS調用？

初始化： -

AsyncHttpClient client = new AsyncHttpClient(); 
      PersistentCookieStore myCookieStore = new PersistentCookieStore(
        getActivity()); 
      // List<Cookie> cookies = myCookieStore.getCookies(); 
      myCookieStore.clear(); 
      // cookies = myCookieStore.getCookies(); 
      client.setCookieStore(myCookieStore); 

      client.get(loginUrl, new JsonHttpResponseHandler() { 

       @Override 
       public void onStart() { 
        super.onStart(); 
        progressBar.setVisibility(View.VISIBLE); 
       } 

       @Override 
       public void onFinish() { 
        super.onFinish(); 
        progressBar.setVisibility(View.GONE); 
       } 

       @Override 
       public void onSuccess(int statusCode, JSONObject userInfo) { 
        super.onSuccess(statusCode, userInfo); 

        String errorMsg = null; 
        try { 
         errorMsg = userInfo.getString("error"); 
        } catch (JSONException e) { 
         e.printStackTrace(); 
        } 

        if (errorMsg != null) { 
         errorMsg = getActivity().getResources().getString(
           R.string.loginFailure) 
           + "\nError: " + errorMsg; 
         tvLoginFailure.setText(errorMsg); 
         tvLoginFailure.setVisibility(View.VISIBLE); 

        } else { 
         Subscriber.setEmail(email); 
         Subscriber.setPassword(password); 
         LoginUtility.saveUserInfo(getActivity(), userInfo); 

         if (Subscriber.getStatus().contentEquals("ACTIVE")) { 
          Intent intent; 
          if (MyApplication.ottMode) { 
           intent = new Intent(getActivity(), 
             OTTMainScreen.class); 

          } else { 
           intent = new Intent(getActivity(), 
             MainActivity.class); 
           intent.putExtra("SIGNEDIN", true); 
          } 
          if (MyApplication.ottMode) { 
           Utility.playSound(getActivity()); 
          } 
          startActivity(intent); 
          getActivity().finish(); 

         } else if (Subscriber.getStatus().contentEquals(
           "SUSPENDED")) { 
          try { 
           String suspendedReason = userInfo 
             .getString("suspendreason"); 
           if (suspendedReason != null 
             && suspendedReason 
               .contentEquals("NO_SUBSCRIPTION")) { 

            new AlertDialog.Builder(getActivity()) 
              .setIcon(
                android.R.drawable.ic_dialog_alert) 
              .setTitle("Account Suspended") 
              .setMessage(
                "Your account doesn't have any active subscription. You need to subscribe to a Package before you can proceed.") 
              .setPositiveButton(
                "Subscribe", 
                new DialogInterface.OnClickListener() { 
                 public void onClick(
                   DialogInterface dialog, 
                   int which) { 
                  recreatePackage(); 
                 } 
                }) 
              .setNegativeButton("Cancel", null) 
              .show(); 

           } else { 
            // TODO 
           } 
          } catch (JSONException e) { 
           e.printStackTrace(); 
          } 

         } else if (Subscriber.getStatus().contentEquals("INIT")) { 
          // TODO 
         } 
        } 
       } 

       @Override 
       public void onFailure(int statusCode, 
         org.apache.http.Header[] headers, String responseBody, 
         Throwable e) { 
        super.onFailure(statusCode, headers, responseBody, e); 
        String msg = getActivity().getResources().getString(
          R.string.loginFailure) 
          + "\nError: " + responseBody; 
        tvLoginFailure.setText(msg); 
        tvLoginFailure.setVisibility(View.VISIBLE); 
       } 
      });

來源

2014-02-17 r4jiv007

請發佈您的AsyncHttpClient初始化代碼。 – vzamanillo

@vzamanillo我已經在這裏添加代碼 – r4jiv007

類似的解決方案：https://stackoverflow.com/questions/42805652/setup-asynchttpclient-to-use-https – user1506104

您需要導入公共服務器證書到您的默認密鑰庫，或者如果你不感興趣的客戶端的認證可以初始化AsyncHttpClient與

AsyncHttpClient asycnHttpClient = new AsyncHttpClient(true, 80, 443);

，但這一招並不安全，因爲使用自定義SSLSocketFactory實施誰忽略SSL證書驗證，看看AsyncHttpClient源代碼。大約在SSLSocketFactory的https://developer.android.com/reference/org/apache/http/conn/ssl/SSLSocketFactory.html

來源

2014-02-17 16:40:41 vzamanillo

「您需要將公共服務器證書導入您的默認密鑰存儲區」可以給出一些鏈接嗎？ – r4jiv007

不客氣:)，一個很好的例子https://stackoverflow.com/questions/20706026/bing-azure-search-api/20789379#20789379 – vzamanillo

我有一個簡單的HTTP客戶端調用HTTPS服務：

import android.util.Log; 
import org.apache.http.HttpResponse; 
import org.apache.http.NameValuePair; 
import org.apache.http.auth.AuthScope; 
import org.apache.http.auth.UsernamePasswordCredentials; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.ResponseHandler; 
import org.apache.http.client.entity.UrlEncodedFormEntity; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.impl.client.AbstractHttpClient; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.apache.http.protocol.HTTP; 

import java.io.ByteArrayOutputStream; 
import java.io.IOException; 
import java.io.InputStream; 
import java.net.URL; 
import java.util.List; 

/** 
*/ 
public class HttpSimpleClient { 

    private static final String TAG = HttpSimpleClient.class.getSimpleName(); 

    private static HttpSimpleClient instance; 

    private HttpSimpleClient(){} 

    public static HttpSimpleClient instance(){ 
     if (instance==null) { 
      instance = new HttpSimpleClient(); 
     } 
     return instance; 
    } 

    public <T> T post(URL url, 
         List<NameValuePair> header, 
         List<NameValuePair> parameter, 
         ResponseHandler<T> responseHandler) throws IOException { 
     return post(url, header, parameter, responseHandler, null, null); 
    } 

    public <T> T post(URL url, 
        List<NameValuePair> header, 
        List<NameValuePair> parameter, 
        ResponseHandler<T> responseHandler, 
        AuthScope proxy, 
        UsernamePasswordCredentials proxyUser) throws IOException { 
     HttpClient httpClient = new DefaultHttpClient(); 
     HttpPost request = new HttpPost(url.toString()); 

     if (header!=null) { 
      for (NameValuePair head : header){ 
       request.setHeader(head.getName(), head.getValue()); 
      } 
      Log.d(TAG, "Aggiunti header: "+ header.size()); 

     } else { 
      // Header di default 
      request.setHeader("Content-Type", "application/x-www-form-urlencoded"); 
      request.setHeader("User-Agent", System.getProperty("http.agent")); 
      Log.d(TAG, "Aggiunti header di defautl"); 
     } 

     if (parameter!=null) { 
      request.setEntity(new UrlEncodedFormEntity(parameter, HTTP.UTF_8)); 
      Log.d(TAG, "Aggiunti parametri: "+ parameter.size()); 
     } 


     if (proxy!=null) { 
      if (proxyUser!=null) { 
       ((AbstractHttpClient) httpClient).getCredentialsProvider().setCredentials(proxy, proxyUser); 

      } else { 
       // TODO gestire proxy senza credenziali 
       ((AbstractHttpClient) httpClient).getCredentialsProvider().setCredentials(proxy, null); 

      } 
      Log.d(TAG, "Impostato Proxy per la connessione"); 
     } 
     return httpClient.execute(request, responseHandler); 
    } 


    public static String httpResponseToString(HttpResponse httpResponse, int bufferSize) throws IOException { 
     InputStream content = httpResponse.getEntity().getContent(); 

     int numRead; 
     byte[] buffer = new byte[bufferSize]; 
     ByteArrayOutputStream outString = new ByteArrayOutputStream(); 
     try{ 
      while ((numRead = content.read(buffer)) != -1) { 
       outString.write(buffer, 0, numRead); 
      } 
     } finally { 
      content.close(); 
     } 
     return new String(outString.toByteArray()); 
    } 
}

我用它在的AsyncTask：

response = HttpSimpleClient.instance().post(
        getServiceURL(), // HTTPS url 
        mHeader, // List<NameValuePair> 
        mParameter, // List<NameValuePair> 
        getResponseHandler() // org.apache.http.client.ResponseHandler 
      );

測試on Android api> = 10

來源

2014-02-17 16:22:00

我不得不使用GET方法！ – r4jiv007

HttpGet request = new HttpGet（url.toString（））; //帶參數的網址而不是HttpPost –

更多信息，下面是我的代碼：

private Map<String, String> mParams; 

public void sendata(View v) throws JSONException { 
    username = (EditText) findViewById(R.id.txtusername); 
    password = (EditText) findViewById(R.id.txtpassword); 

    final ProgressDialog pDialog = new ProgressDialog(this); 
    pDialog.setMessage("Loading..."); 
    pDialog.show(); 
    JSONObject j = new JSONObject(); 
    j.put("password", password.getText()); 
    j.put("username", username.getText()); 
    j.put("Deviceid", 123456789); 
    j.put("RoleId", 1); 
    String url = Url; 
    AsyncHttpClient client = new AsyncHttpClient(); 
    RequestParams params = new RequestParams(); 
    params.put("json", j.toString()); 
    client.post(url, params, new JsonHttpResponseHandler() { 
     @SuppressLint("NewApi") 
     public void onSuccess(JSONObject response) { 
      pDialog.hide(); 
      JSONObject jsnObjct; 
      try { 
       JSONObject json = (JSONObject) new JSONTokener(response 
         .toString()).nextValue(); 
       JSONObject json2 = json.getJSONObject("Data"); 
       JSONArray test = (JSONArray) json2 
         .getJSONArray("PatientAllergies"); 
       for (int i = 0; i < test.length(); i++) { 
        json = test.getJSONObject(i); 
        System.out.print(json.getString("PatientId")); 
        System.out.print(json.getString("Id")); 
        System.out.print(json.getString("AllergyName")); 
        System.out.print(json.getString("Reaction")); 
        System.out.print(json.getString("OnSetDate")); 
       } 
      } catch (JSONException e) { 
       e.printStackTrace(); 
      } 
     } 

     public void onFailure(int statusCode, Header[] headers, String res, 
       Throwable t) { 
      pDialog.hide(); 
     } 
    }); 

} 
JSONObject jsonObject; 

private void parsejson(JSONObject response) { 

    try { 
     jsonObject = response; 
     System.out.print(response.toString()); 
     JSONObject jsnObjct = jsonObject.getJSONObject("Data"); 
     System.out.print(jsonObject.toString()); 
     jsnObjct = jsnObjct.getJSONObject("PhysicianDetail"); 

     System.out.print(jsnObjct.toString()); 

    } catch (JSONException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } 

}

來源

2015-10-17 04:35:55

你也可以解決這個問題，以增加該1行。

asyncHttpClient.setSSLSocketFactory(MySSLSocketFactory.getFixedSocketFactory());

來源

2016-01-23 19:19:12 JavadKhan

謝謝。它解決了我的問題。 – Kutbi

不客氣！ – JavadKhan

使用MySSLSocketFactory時必須提及：「警告！這忽略了每個設備上的SSL證書驗證，請謹慎使用。」 – rbrisuda

如何使用AsyncHttpClient進行HTTPS調用？

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