我想顯示我的查詢的正確的時間戳。我的數據庫中的日期是這個日期時間戳記設置在歐洲/柏林。這是在我的服務器設置,我總是得到這個結果。如何在mysql中選擇查詢時顯示正確的時間戳?
2017年5月26日9時05分58秒
我想顯示從我的查詢日期。這裏是我的查詢代碼
select logs.action_date_time from AuditLogs
我怎麼能在這裏轉換logs.action_date_time日期在我的地方在菲律賓?我應該
2017-05-26T09看到這樣的結果:05:58 + 02:00
我尋找它在谷歌的UNIX_TIMESTAMP,但我沒有看到他們在使用任何樣品從查詢中選擇之前。我爲此使用了symfony。我只是給出了我的上述示例代碼的結果的摘要。
const SELECT =
'SELECT logs.id, logs.object_id AS objectId, logs.object_type AS objectType, logs.object_name AS objectName, '.'logs.action, logs.action_date_time AS actionDateTime, logs.action_status AS actionStatus, logs.subject, logs.user, '.'logs.description, logs.ip, logs.param03_value AS userId, logs.param04_value AS userDisplayName ';
public function getNext($params)
{
// Hardcode for now
$limit = $params['limit'] ? (int) $params['limit'] : self::DEFAULT_LIMIT;
$limit++;
$select = self::SELECT;
$whereClause = $this->constructWhereClause($params);
$sql = "
$select FROM spoke.audit_logs AS logs
$whereClause
ORDER BY logs.action_date_time DESC, logs.id DESC
LIMIT $limit";
if ($params['cursor']) {
$now = new \DateTime();
$datetime = $now->getTimestamp();
if (isset($params['datetime'])) {
$datetime = $params['datetime'];
}
$whereClause = $this->constructWhereClause($params, 'logs1', false);
$sql = "
$select
FROM spoke.audit_logs logs1, spoke.audit_logs logs
WHERE logs1.id = logs.id
$whereClause
AND logs1.action_date_time <= '$datetime'
AND (logs1.id < {$params['cursor']} OR logs1.action_date_time < '$datetime')
ORDER BY logs1.action_date_time DESC, logs1.id DESC
LIMIT $limit";
}
$stmt = $this->getEntityManager()->getConnection()->query($sql);
return $stmt->fetchAll(\PDO::FETCH_ASSOC);
}
我嘗試轉換這個,但時間提前2小時。 – user3818576
但我嘗試了你給我的鏈接 – user3818576