我怎麼能讓Math.random（）在每次調用存儲在其中的變量時都返回不同的值？

Question

我現在有一項任務，它要求我使用Math.random()保存在一個變量中，我已經命名爲randomNumberBetween0and5（它實際上是Math.floor((Math.random() * 5) + 0);，它返回一個介於0和5之間的數字。我使用這個數字來指代其他地方某些數組的索引）我在代碼中多次調用它兩次，但是我需要Math.random()只執行一次，然後將它的值存儲在randomNumberBetween0and5變量中以備後用，而不會更改，如果我再次調用變量兩次或三次。

我試圖將randomNumberBetween0and5的值存儲在另一個變量中，並且（如預期的那樣）並不能幫助解決問題。任何幫助肯定會感激！謝謝！

（這裏的一切都只是在案件的代碼，你想看到它。）

var names = ["Lázaro", "Aviram", "Samuel", "Miles", "Felix"]; // Defining an array of random names 
var people = []; // Declaring the array to hold each instance of the 'Person' object 

// For() to create one new instance thrice for three names of the 'names' array in the 'Person' object defined in 'person.js' 

for (var i=0;i < 3;i++) { 
    var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); // Randomly choosing a number for the arrays to be passed to the 'Person()' object's methods defined in 'person.js' 
    var newInstance = new Person.generate(names.splice(randomNumberBetween0and5,randomNumberBetween0and5+1),Person.actions[randomNumberBetween0and5],Person.jobs[randomNumberBetween0and5],i+1); // Creating a new instance of the 'Person()' object and passing a random name, action (from the Person object's properties), and job (also from the Person object's properties), along with the current loop number for the row to use (i begins at 0 so it becomes 1,2,3 instead of 0,1,2 when a 1 is added) 
    //people.push(newInstance); // Adding the new instance to the 'people' array of instances 
    people.push(newInstance); // Adding the newly created instance of 'Person' to the variable 'people' 
}; // Ending the for() 

console.log(people); // Logging the 'people' array for debugging 
console.log("Main.js has been completely interpreted -- Nothing has broken yet."); // Reassuring console log to state that this file has completely executed without breaking 

Answer 1

也許這個段解釋了它：

// When Math.floor is initially called it creates the random number 
// store this in variable: randomNumberBetween0and5 
var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); 

for (var i = 0; i < 10; i++) { 
    // randomNumberBetween0and5 will never change in this function 
    console.log(randomNumberBetween0and5); 
} 

問題在你的代碼是你在循環中調用Math.floor。這將始終創建一個隨機。

與您的代碼試試這個：

var names = ["Lázaro", "Aviram", "Samuel", "Miles", "Felix"]; 
var people = []; 
var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); 

for (var i=0;i < 3;i++) { 
    console.log('randomNumberBetween0and5 is: ' + randomNumberBetween0and5); 
    var newInstance = new Person.generate(names.splice(randomNumberBetween0and5,randomNumberBetween0and5+1),Person.actions[randomNumberBetween0and5],Person.jobs[randomNumberBetween0and5],i+1); 
    people.push(newInstance); 
}; 

Answer 2

它是好的，如果你讓randomNumberBetween0and5陣列，使得它能夠同時存儲3個不同的數字？

var randomNumberBetween0and5 = []; 
for(var i = 0; i < 3; i++){ 
    randomNumberBetween0and5.push(Math.floor(Math.random()*5)); 
    //do stuff with randomNumberBetween0and5[i] 
} 

Answer 3

FYI的Math.random（）返回0和1之間的數字由5乘以你之間的一個數字0和5.您需要Math.round（的Math.random（）* 5）正確設置你的變量。只要Math.random返回1，Math.floor只會讓你得到5，我不相信會這樣。