如何將「嘗試」放在onclicklistener中,所以當我按下按鈕時它會發送數據?但是我這樣做,當我運行它時,它總是崩潰。按下按鈕時發送httpdata?
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
name = (EditText) findViewById(R.id.name);
pass = (EditText) findViewById(R.id.password);
b1 = (Button) findViewById(R.id.btn);
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www2.park.se/~ts5124/receive.php");
try {
JSONObject json = new JSONObject();
json.put("name","Tim");
json.put("password", "hje");
StringEntity se;
se = new StringEntity(json.toString());
// Add your data
httppost.setEntity(se);
httppost.setHeader("Accept", "application/json");
httppost.setHeader("Content-type", "application/json");
Log.i(TAG, json.toString());
// Execute HTTP Post Request
httpclient.execute(httppost);
} catch (JSONException je) {
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
我已經完成了按鈕之前,它已經工作,爲什麼有一個問題,當它是一個「嘗試」的onClick?
如果添加上你得到了什麼異常,並詳細信息的堆棧跟蹤這將有助於到什麼線路。 – 2012-03-12 07:47:24
@Runkeball:請同時上傳日誌堆棧跟蹤。 – 2012-03-12 07:51:14
我已將它貼在答案下。 – simtaxman 2012-03-13 09:21:46