過濾嵌套關係Django的REST框架

我有兩個型號，看起來像下面這樣：過濾嵌套關係Django的REST框架

class Subject(models.Model): 

    subject_code = models.CharField(max_length=12, unique=True) 
    name = models.CharField(max_length=100) 
    dept_code = models.CharField(max_length=6)

和...

class Subject_assessment(models.Model):  
    subject_code = models.ForeignKey(Subject, related_name='sub_assessments') 
    year = models.CharField(max_length=4) 
    name = models.CharField(max_length=50)

我已經創建了我的連載以這樣的方式，當我找回一個主題，我也檢索與該主題相關的評估。我使用下面的序列化來實現：

class AssessmentsSerializer(serializers.ModelSerializer): 
class Meta: 
    model = Subject_assessment 
    fields = (
     "subject_code", "year", "name" 
    ) 

class SubjectSerializer(serializers.ModelSerializer): 
sub_assessments = AssessmentsSerializer(many=True) 
class Meta: 
    model = Subject 
    fields = (
     "subject_code", "name", "dept_code",    
     "sub_assessments" 
    )

此代碼工作完全如預期，因爲它給了我這樣的結果：

{ 
"subject_code":"ECR2243", 
"name":"Statistics", 
"dept_code":"Stats", 
"sub_assessments":[ 
    { 
     "subject_code":"ECR2243", 
     "year":"2017", 
     "name":"Test 1" 
    }, 
    { 
     "subject_code":"ECR2243", 
     "year":"2016", 
     "name":"Test 1" 
    } 
] 
}

我的問題是，我希望檢索評估只針對特定的一年。例如，如果我作爲感興趣的年份通過，我不希望像我目前正在獲取的那樣檢索評估。

任何人都可以請協助我如何構建我的代碼，以完成此任務。先謝謝你。

編輯1 我views.py如下：

class SubjectViewSet(viewsets.ModelViewSet): 
serializer_class = SubjectSerializer 
lookup_field = 'subject_code' 

def get_queryset(self): 
    qry_subject_code = self.request.GET.get('subject_code') 
    retrieved_sub = Subject.objects.filter(subject_code=qry_subject_code) 
    return retrieved_sub

來源

2017-02-10 Tatenda

你能擴大與view.py – marin

檢查你的問題http://www.django-rest-framework.org/api-guide/serializers/#additional-keyword-arguments 。它詳細介紹瞭如何將額外參數傳遞給序列化程序。它可以幫助您構建解決方案。 –

@marin我已添加我的views.py – Tatenda

這是爲我工作的解決方案這個問題：

class FilteredAssessmentsSerializer(serializers.ListSerializer): 
    def to_representation(self,data): 
     qry_year = self.context['request'].GET.get('year') 
     data = data.filter(year=qry_year) 
     return super(FilteredAssessmentsSerializer, self).to_representation(data) 

class AssessmentsSerializer(serializers.ModelSerializer): 
    class Meta: 
     model = Subject_assessment 
     list_serializer_class = FilteredAssessmentsSerializer 
     fields = '__all__' 

class SubjectSerializer(serializers.ModelSerializer): 
    sub_assessments = AssessmentsSerializer(many=True) 
    class Meta: 
     model = Subject 
     fields = (
      "subject_code", "name", "dept_code", 
      "faculty_code", "university_code", "description", 
      "sub_assessments" 
     )

參考：我結合以下解決方案來想出一個適合我的。

How can I apply a filter to a nested resource in Django REST framework?

https://stackoverflow.com/a/28354281/7210105

來源

2017-02-11 15:29:49 Tatenda

你可以嘗試用此查詢：

retrieved_sub = Subject_assessment.objects.filter(subject_code__in=Subject.objects.filter(subject_code=qry_subject_code),year='2014').all()

來源

2017-02-10 10:59:01 marin

不工作。（）在那裏的原因是什麼？ – Tatenda

你可以在打電話給URL時打印＃retrieve_sub＃嗎？因爲.all（）將返回查詢中的所有值。 – marin

不知道你是否正確地得到我的問題。我的代碼是從數據庫返回結果，檢查問題。我的問題是如何篩選嵌套序列化器的結果到 – Tatenda

過濾嵌套關係Django的REST框架

回答

相關問題