如何使用列表的索引做串插在一個for循環在python

Question

我有一個名單，我希望把它的元素裏面一個for循環的字符串是這樣的：

my_list = ["Germany", "England", "Spain", "France"] 
for this in that: 
    do stuff 
    print(my_list[0]+ some other stuff) 

輸出應該是像：

Germany + some other stuff 
England + some other stuff 
Spain + some other stuff 
France + some other stuff 

我怎麼能迴路串插指數呢？

謝謝！

編輯：循環有點不同。它更像這樣：

for foo in bar: 
    another_bar = [] 
    for x, y in foo: 
     do stuff 
     a = object.method() 
     another_bar.append(my_list[0]+a) 

我需要將列表的字符串放入第二層嵌套循環。這裏不能使用zip。

Answer 1

我相信你認爲that與my_list的長度相同。如果是這樣，您可以使用zip並行迭代兩個容器。

my_list = ["Germany", "England", "Spain", "France"] 
my_other_list = [' is great at football', ' has good years in rugby', ' has Renaldo', ' is, well...'] 

def foo(bar): 
    return bar + '!' 

for country, bar in zip(my_list, my_other_list): 
    other = foo(bar) 
    print(country + other) 

# Output: 
# Germany is great at football! 
# England has good years in rugby! 
# Spain has Renaldo! 
# France is, well...! 

Answer 2

您可以使用內置功能zip()。 zip允許並行處理每個列表：

創建一個迭代器，用於聚合來自每個迭代器的元素。

返回元組的迭代器，其中元組包含來自每個參數序列或迭代的第i個元素。當最短的輸入迭代耗盡時，迭代器停止。使用單個迭代參數，它將返回1元組的迭代器。沒有參數，它返回一個空的迭代器。

my_list = ["Germany", "England", "Spain", "France"] 
for country, this in zip(my_list, that): 
    # do stuff 
    print(country + that) 

如果您的列表大小不同，您可以使用itertoos.zip_longest：

作出這樣的聚合來自各個iterables的元素的迭代器。如果迭代的長度不均勻，缺少的值將用fillvalue填充。迭代繼續下去，直到最長的迭代耗盡。

from itertools import zip_longest 

my_list = ["Germany", "England", "Spain", "France"] 
for country, this in zip_longest(my_list, that): 
    # do stuff 
    print(country + that) 

Answer 3

我希望這可以幫助你。

for index, this in enumerate(that): 
    do stuff 
    print(my_list[index]+ some other stuff)