如何對結果集進行旋轉

我的任務是監控SQL AlwaysON的性能。我寫了一個腳本，將返回AlwaysOn可用性組信息如下：如何對結果集進行旋轉

; 
 
WITH basicaginfo AS(
 
SELECT 
 
     
 
     ag.name AS AvailabilityGroupName, 
 
     cs.replica_server_name AS NodeName, 
 
     rs.role_desc, 
 
     rs.synchronization_health_desc, 
 
     DB_NAME(drs.database_id) AS DatabaseName 
 
     
 

 

 
FROM 
 
     sys.availability_groups ag 
 
        join 
 
     sys.dm_hadr_availability_replica_cluster_states cs on ag.group_id = cs.group_id 
 
        join 
 
     sys.dm_hadr_availability_replica_states rs ON (ag.group_id=rs.group_id AND cs.replica_id = rs.replica_id) 
 
        join 
 
     sys.dm_hadr_database_replica_states drs ON (ag.group_id=drs.group_id AND cs.replica_id = drs.replica_id) 
 
       
 
WHERE 
 
     cs.replica_server_name = @@SERVERNAME 
 
     ), 
 

 
    
 
     AG_Stats AS 
 
        (
 
        SELECT AR.replica_server_name, 
 
           HARS.role_desc, 
 
           Db_name(DRS.database_id) [DBName], 
 
           DRS.last_commit_time 
 
        FROM sys.dm_hadr_database_replica_states DRS 
 
        INNER JOIN sys.availability_replicas AR ON DRS.replica_id = AR.replica_id 
 
        INNER JOIN sys.dm_hadr_availability_replica_states HARS ON AR.group_id = HARS.group_id 
 
          AND AR.replica_id = HARS.replica_id 
 
        ), 
 
     Pri_CommitTime AS 
 
        (
 
        SELECT replica_server_name 
 
           , DBName 
 
           , last_commit_time 
 
        FROM AG_Stats 
 
        WHERE role_desc = 'PRIMARY' 
 
        ), 
 
     Sec_CommitTime AS 
 
        (
 
        SELECT replica_server_name 
 
           , DBName 
 
           , last_commit_time 
 
        FROM AG_Stats 
 
        WHERE role_desc = 'SECONDARY' 
 
        ) 
 
SELECT 
 
\t \t bb.*, 
 
\t \t p.replica_server_name [primary_replica] 
 
     , s.replica_server_name [secondary_replica] 
 
     , DATEDIFF(ss,s.last_commit_time,p.last_commit_time) AS [Sync_Lag_Secs] 
 
     
 
FROM Pri_CommitTime p 
 
LEFT JOIN Sec_CommitTime s ON [s].[DBName] = [p].[DBName] 
 
left join basicaginfo bb on p.replica_server_name=bb.NodeName and p.DBName=bb.DatabaseName

下面是輸出的圖像： https://i.stack.imgur.com/jLcMt.png

如何可以「透視」的結果爲1行這將是這個樣子：

AvailabilityGroupName Primary  LAB-SCB-SQL02 LAB-LAS-SQL01 LAB-LAS-SQL02 Sync_Lag_Secs 
 
    LAB-VIP-USADB  LAB-SCB-SQL01 HEALTHY \t   HEALTHY \t  HEALTHY \t  max(3)

我要尋找的作品像「圖表」命令，在Splunk的地方通過secondary_replica

來源

2017-08-02 Nicholas Qi

搜索谷歌左右的「PIVOT數據」 – Alex

這將替換您的主查詢跨越多個對值的列的方式。 CTE保持不變。

SELECT AvailabilityGroupName, NodeName, role_desc, [primary_replica], 
    -- Replace Server1, 2, 3 etc with your specific values. Keep square brackets 
    [Server1], [Server2], [Server3], [Max_Sync_Lag_Secs] 
FROM(
    SELECT 
     bb.AvailabilityGroupName, bb.NodeName, bb.role_desc, bb.synchronization_health_desc, bb.DatabaseName, 
     p.replica_server_name AS [primary_replica], 
     s.replica_server_name AS [secondary_replica], 
     DATEDIFF(ss,s.last_commit_time,p.last_commit_time) AS [Sync_Lag_Secs], 
     MAX(DATEDIFF(ss,s.last_commit_time,p.last_commit_time)) OVER(PARTITION BY NULL) AS [Max_Sync_Lag_Secs] 
    FROM Pri_CommitTime AS p 
    LEFT JOIN Sec_CommitTime s ON [s].[DBName] = [p].[DBName] 
    LEFT JOIN basicaginfo bb on p.replica_server_name=bb.NodeName and p.DBName=bb.DatabaseName 
) AS Data 
PIVOT(
    -- Replace Server1, 2, 3 etc with your specific values. Keep square brackets 
    MAX(synchronization_health_desc) FOR [secondary_replica] IN([Server1], [Server2], [Server3])) AS PivotedData;

有用的資料來源：

SQL Server Pivot Table with multiple column aggregates

MSDN

來源

2017-08-03 09:19:11 Alex

如何對結果集進行旋轉

回答

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