Django多個html參數

Question

我試圖捕捉兩個參數，但我不知道如何通過html發送它們。

這是urls.py：

app_name = 'series' 
urlpatterns = [ 
    url(r'^$', views.index, name='index'), 
    url(r'^(?P<serie_id>[0-9]+)/$', views.season, name='season'), 
    url(r'^(?P<serie_id>[0-9]+)/(?P<season_id>[0-9]+)/$', views.chapter, name='chapter'), 
    url(r'^login/$', views.login, name='login'), 
] 

這是HTML：

<ul> 
{% for season in season_list %} 
    <li><a href="{% url 'series:chapter' season.id %}">{{ season.season_name }}</a></li> 
{% endfor %} 
</ul> 

這是視圖：

def chapter (request, serie_id, season_id): 
    season = Season.objects.get(pk=season_id) 
    chapter_list = season.chapter_set.all() 
    return render(request, 'series/serie.html', {'chapter_list': chapter_list}) 

我有此錯誤：

Reverse for 'chapter' with arguments '(1,)' and keyword arguments '{}' not found. 1 pattern(s) tried: [u'series/(?P<serie_id>[0-9]+)/(?P<season_id>[0-9]+)/$'] 

我該如何解決它？根據您的urls.py

Answer 1

，您對URL兩種選擇：

呼叫series:season只用系列ID（url(r'^(?P<serie_id>[0-9]+)/$', views.season, name='season')）：同系列的ID

<ul> 
{% for season in season_list %} 
    <li><a href="{% url 'series:season' series.id %}">{{ season.season_name }}</a></li> 
{% endfor %} 
</ul> 

或致電series:chapter（url(r'^(?P<serie_id>[0-9]+)/(?P<season_id>[0-9]+)/$', views.chapter, name='chapter')）和季節編號 - 我不知道series來自哪裏，所以你需要修改此代碼才能使用。

<ul> 
{% for season in season_list %} 
    <li><a href="{% url 'series:chapter' series.id season.id %}">{{ season.season_name }}</a></li> 
{% endfor %} 
</ul>