通過AJAX變量到PHP

Question

 function viewDetail(pid) 
     { 
       $.post("product.php", { data: pid}); 

       <?php 
       $data = $_POST['data']; 
       retrieve_product_detail($data); 
      ?> 
     } 

這個方法我試過了，但是「PID」的價值是不會功能retrieve_product_detail($data)請幫助我，我如此堅持soooooooooooon

Answer 1

var url = "myurl/myurl.php"; 
var params = "param1=sth&param2=sth"; 
http.open("POST", url, true); 

//header information along with the request 
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 
http.setRequestHeader("Content-length", params.length); 
http.setRequestHeader("Connection", "close"); 

http.onreadystatechange = function() {//Call a function when the state changes. 
    if(http.readyState == 4 && http.status == 200) { 
     alert(http.responseText); 
       //or do whatever you want to with the response 
    } 
} 
http.send(params);