如何從數組中的字符串中刪除字母？

Question

我有這個數組AR，我需要從它的每個單詞中刪除元音。我如何去做這件事？我已經嘗試過.pop和.remove，但這不起作用。

ar=["house","place","oipa"] 

def noWovels(inList): 
    wovels=["a","e","i","o","u","y"] 
    for word in inList: 
     for letter in word: 
      if letter in wovels: 
       inList[word].remove(letter) ? 
       inList.replace(letter,"") ? 
       word.pop(letter) ? 
    return inList 

print(noWovels(ar)) 

Answer 1

列表理解應該是整齊的。

>>> [''.join(j for j in i if j not in 'aeiou') for i in ar] 
['hs', 'plc', 'p'] 

Answer 2

您可能使用簡單的列表解析表達爲達到相同的：

>>> vowels = 'aieou' 
>>> word_list = ["house","place","oipa"] 
>>> [''.join(c for c in word if c not in vowels) for word in word_list] 
['hs', 'plc', 'p'] 

，或者可選地使用filter列表解析（未建議）作爲內：

>>> [''.join(filter(lambda c: c not in vowels, word)) for word in word_list] 
['hs', 'plc', 'p'] 

---

說明：

這些列表理解表情邏輯等同於：

new_list = [] 
for word in word_list: 
    new_word = '' 
    for c in word: 
     if c not in vowels: 
      new_word += c 
    new_list.append(new_word) 

Answer 3

基於您的代碼：

ar = ["house", "place", "oipa"] 

def noWovels(inList): 
    wovels = ["a", "e", "i", "o", "u", "y"] 
    for i, word in enumerate(inList): 
     for w in wovels: 
      word = word.replace(w, "") 
     inList[i] = word 

    return inList 

print(noWovels(ar))