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jQuery彈出框未關閉。它可以正確打開,但當我點擊close或「x」時不會關閉。jQuery彈出框未關閉
如果我刪除#從href =「#」,那麼該框將關閉,但加載頁面的URL。我想在不加載網址的情況下關閉此框。
我有什麼問題?
jQuery(function() {
//----- OPEN
jQuery('[data-popup-open]').on('click', function(e) {
var targeted_popup_class = jQuery(this).attr('data-popup-open');
jQuery('[data-popup="' + targeted_popup_class + '"]').fadeIn(350);
e.preventDefault();
});
//----- CLOSE
jQuery('[data-popup-close]').on('click', function(e) {
var targeted_popup_class = jQuery(this).attr('data-popup-close');
jquery('[data-popup="' + targeted_popup_class + '"]').fadeOut(3);
e.preventDefault();
});
});
/* Outer */
.popup {
width:100%;
height:100%;
display:none;
position:fixed;
top:0px;
left:0px;
background:rgba(0,0,0,0.75);
}
/* Inner */
.popup-inner {
max-width:700px;
width:90%;
padding:40px;
position:absolute;
top:50%;
left:50%;
-webkit-transform:translate(-50%, -50%);
transform:translate(-50%, -50%);
box-shadow:0px 2px 6px rgba(0,0,0,1);
border-radius:3px;
background:#fff;
}
/* Close Button */
.popup-close {
width:30px;
height:30px;
padding-top:4px;
display:inline-block;
position:absolute;
top:0px;
right:0px;
transition:ease 0.25s all;
-webkit-transform:translate(50%, -50%);
transform:translate(50%, -50%);
border-radius:1000px;
background:rgba(0,0,0,0.8);
font-family:Arial, Sans-Serif;
font-size:20px;
text-align:center;
line-height:100%;
color:#fff;
}
.popup-close:hover {
-webkit-transform:translate(50%, -50%) rotate(180deg);
transform:translate(50%, -50%) rotate(180deg);
background:rgba(0,0,0,1);
text-decoration:none;
}
<a class="btn" data-popup-open="popup-1" href="#">Open Popup #1</a>
<div class="popup" data-popup="popup-1">
<div class="popup-inner">
<h2>Have some feedback?</h2>
<p>Use the feedback box below if you have a question, comment or general feedback.</p>
<p><a data-popup-close="popup-1" href="#">Close</a></p>
<a class="popup-close" data-popup-close="popup-1" href="#">x</a>
</div>
</div>
您可以使用$(...)而不是jQuery的(...),以避免錯字問題 – Vijai
感謝Vijai。我使用Wordpress,所以我想我需要更改$ jQuery? –