2017-03-06 46 views
2

我正在編寫重命名報告並將它們放入文件夾的腳本。按文件名重命名報告

報告名稱必須更改爲正確的日期(日期必須在文件名中)。

例如我有一個名爲「Report_2015_02」的報告/我必須從文件名減去一個月 - 而不是系統時間

在這種情況下,新的報告名稱必須是「Report_2015_01」

但在我使用SYSTEMTIME的瞬間,所以REPORTNAME將是「Report_2017_02」因爲SYSTEMTIME(2017_03)減去一個月的2017_02。 ..

問:如何使用文件名的日期而不是系統時間?

這裏是我的代碼:

#today's date (year-month-day) 
$todaydate = Get-Date -Format yyyy-MM-dd 

#arrays (today => systemtime) 
$todaydate = $todaydate.Split('-') 
$todaydate[0] #year 
$todaydate[1] #month 
$todaydate[2] #day 

#arrays yesterday (systemtime - one day) 
$yesterdaysdate = Get-Date((Get-Date).AddDays(-1)) -Format yyyy-MM-dd 
$yesterdaysdate = $yesterdaysdate.Split('-') 
$yesterdaysdate[0] #year 
$yesterdaysdate[1] #month 
$yesterdaysdate[2] #day 

#arrays yesterday (systemtime - one day) 
$lastmonth = Get-Date((Get-Date).AddMonths(-1)) -Format yyyy-MM-dd 
$lastmonth = $lastmonth.Split('-') 
$lastmonth[0] #year 
$lastmonth[1] #month 
$lastmonth[2] #day 

#Example 1: Filename "Report_Telephone_yyyy-mm" => in this case "Report_Telephone_2016-12" 
#it renames the file -> minus one month, so the name must be "Report_Telephone_2016-11" 
$filename='Report_Telephone_'+ $lastmonth[0]+'-'+ $lastmonth[1] + '.xlsx' 

write-host $filename 
rename-item 'c:\Reporting\Report_Telephone_' + $todaydate[0] +'-' + $todaydate[1] + '.xlsx' -NewName $filename 

$sourcepath='C:\Reporting\'+ $filename 
write-host $sourcepath 
$destinationpath='C:\Reporting\'+ $lastmonth[0]+'\'+ $lastmonth[1] 
write-host $destinationpath 
if(test-path $destinationpath) 
{ 

} 
else 
{ 
    mkdir $destinationpath 
} 
move-item -path $sourcepath -destination $destinationpath 



#Example 2: Filename "Report_Outlook_yyyy-mm-dd" => in this case "Report_Outlook_2016-12-14" 
#it renames the file -> minus one day, so the name must be "Report_Outlook_2016-12-13" 

$filename='Report_Outlook_'+ $lastmonth[0]+'-'+ $lastmonth[1] + '.xlsx' 

write-host $filename 
rename-item 'c:\Reporting\Report_Outlook_' + $todaydate[0] +'-' + $todaydate[1] + '.xlsx' -NewName $filename 

$sourcepath='C:\Reporting\'+ $filename 
write-host $sourcepath 
$destinationpath='C:\Reporting\'+ $yesterdaysdate[0]+'\'+ $yesterdaysdate[1] 
write-host $destinationpath 
if(test-path $destinationpath) 
{ 

} 
else 
{ 
    mkdir $destinationpath 
} 
move-item -path $sourcepath -destination $destinationpath 



#that is just for generating log-files 
[System.IO.File]::WriteAllText("$sourcepath\Protokoll_$todaydate.xls", $output) 

回答

1

您可以使用一個簡單的正則表達式搶月份,它爲一個整數,。減去 1,最後格式它作爲一個字符串小數點後兩位:

$fileName = 'Report_2015_02' # Probably want to use Get-ChildItem here... 
$fileMonth = [int][regex]::Match($fileName, '\w+_\d+_(\d+)').Groups[1].Value 
$fileMonth = "{0:D2}" -f ($fileMonth - 1)